The force F has a magnitude of 520 lb and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express F as its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. 1 15" F = 520 lb j+ i k) B M 8" Answers: Vector F = (520 lb)(i Scalar components Fx= i Fy= i F₂= i 11" lb lb lb A i+ i

The force F has a magnitude of 520 lb and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express F as its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. 1 15" F = 520 lb j+ i k) B M 8" Answers: Vector F = (520 lb)(i Scalar components Fx= i Fy= i F₂= i 11" lb lb lb A i+ i

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

12.0 B = 5.0 F = 20.0 86400 365) %3D 24 (6)60) = Esc 60° A = 10.0 30 30° 53° D = 20.0 37° Assuming the +x-axis is horizontal to the right for the vectors in the figure, find the following scalar products. a. Ā . B- b. Č - (- 3) - c. Dx F- a. (5 x F) - ( x Ã) -
Two vectors have the following magnitude, A = 11.5m and B = 7.5m . Their vector product is A* B=-2.5m i+12. m k
If force F is expressed as a Cartesian vector, it would be F = Fx i + Fy j + Fz k, where i, j, and k are unit vectors. Find the nearest Fx, Fy and Fz all in lb. 5 ft B7 ft X Z Fx = -70.5; Fy = 57.2; and Fz = -83.2 Fx = 98.2; Fy = -44.7; and Fz = -57.2 Fx = -70.4; Fy = 88.2; and Fz= -59.4 Fx = 59.4; Fy = -88.2; and Fz = -83.2 F = 135 lb 10 ft 70° 30° A y
Given M = 6 î + 5 j – 6 k and N = 3 î - 3 j - 3 k, calculate the vector product M x N. j +
Determine a unit vector parallel to the resultant vector of 2i + 9j – 9k lb, – 2i – 6j + 8k lb, and - 2i + 6j + 4k lb. i + V X k) lb R = ( -0.206 0.92 j+ | 0.3
For vectors ū and ū, suppose ||ü|| - 5, the angle between the vectors is 170 degrees, and the dot product ü-i = -8. Find the magnitude of vector i . Leave at least 4 decimals place. Don't round.
The force F has a magnitude of 540 N. Express F as a vector in terms of the unit vectors i and j. Identify the x and y scalar components of F. Assume F = 540 N, 0 = 28% 0 j) N T Answers: F = (i Fx i Fy= i II F i+ i N N
The force F has a magnitude of 770 N. Express F as a vector in terms of the unit vectors i and j. Identify the x and y scalar components of F. Assume F-770 N, 8-23° Answers: F- i i+ i j) N Fx- i N Fy- i N
The force F has a magnitude of 610 N. Express F as a vector in terms of the unit vectors i and j. Identify the x and y scalar components of F. Assume F = 610 N, 0 = 40° Answers: F = (1 DN Fx= i i İ+ N N
Assume the three force vectors interest at a single point. P1= i + 3j + 4kP2= 2i + 7j - kP3= -i + 4j + 2kWhat is the magnitude of the resultant force vector, R?
Vector A =5i+2j and vector B =2i−3j+4k. a) What is the cross product A⃗ ×B⃗ ? Find the x-component. b)Find the y-component. c)Find the z-component.
Let the x-, y-, and z-axes be identified as axes 1, 2, and 3, respectively. Find the angle between A and axis 2 if A=0.17, Ay = 2.76, and A₂ = 2.98. [Hint: Write the unit vector in the direction of axis 2 and use A. B = A₂ B₂ + A, B, + A₂B₂ = AB cos 1 Φ Record your numerical answer below, assuming three significant figures. A