If force F is expressed as a Cartesian vector, it would be F = Fx i + Fy j + Fz k, where i, j, and k are unit vectors. Find the nearest Fx, Fy and Fz all in lb. 5 ft B 76 Z F = 135 lb 10 ft 70° 30° A y
If force F is expressed as a Cartesian vector, it would be F = Fx i + Fy j + Fz k, where i, j, and k are unit vectors. Find the nearest Fx, Fy and Fz all in lb. 5 ft B 76 Z F = 135 lb 10 ft 70° 30° A y
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![### Cartesian Vector Components of Force F
When a force \( F \) is expressed as a Cartesian vector, it is written as:
\[ \mathbf{F} = F_x \mathbf{i} + F_y \mathbf{j} + F_z \mathbf{k} \]
where \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \) are unit vectors in the x, y, and z directions, respectively.
#### Problem Statement:
Given the force \( \mathbf{F} \) with a magnitude of 135 lb, the task is to find the nearest values of \( F_x \), \( F_y \), and \( F_z \). The diagram provided gives a visual representation of the force \( \mathbf{F} \) and the angles involved.
#### Diagram Description:
- There is a 3-dimensional coordinate system (\( x \), \( y \), and \( z \) axes).
- Point \( A \) is where the force vector \( \mathbf{F} \) is applied.
- The vector \( \mathbf{F} \) makes an angle of 70° with the horizontal projection \( AB \) and an angle of 30° with the vertical plane.
- The horizontal projection \( AB \) extends 10 feet from the origin along the plane.
- The base \( B \) is 5 feet along the x-axis and 7 feet along the y-axis from the origin.
#### Possible Solution Choices:
1. \( F_x = -70.5 \); \( F_y = 57.2 \); \( F_z = -83.2 \)
2. \( F_x = 98.2 \); \( F_y = -44.7 \); \( F_z = -57.2 \)
3. \( F_x = -70.4 \); \( F_y = 88.2 \); \( F_z = -59.4 \)
4. \( F_x = 59.4 \); \( F_y = -88.2 \); \( F_z = -83.2 \)
#### Calculation Methodology:
To find the components \( F_x \), \( F_y \), and \( F_z \) of the force \( \mathbf{F} \), we can use trigonometric relationships from the angles provided. By projecting the force vector onto the coordinate axes and applying cosine and sine functions,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a85083f-c711-4fe4-a0ea-d798364bd78d%2Fcec05379-f426-4e39-a7c0-1f2cb138e796%2Fqzooy8d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Cartesian Vector Components of Force F
When a force \( F \) is expressed as a Cartesian vector, it is written as:
\[ \mathbf{F} = F_x \mathbf{i} + F_y \mathbf{j} + F_z \mathbf{k} \]
where \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \) are unit vectors in the x, y, and z directions, respectively.
#### Problem Statement:
Given the force \( \mathbf{F} \) with a magnitude of 135 lb, the task is to find the nearest values of \( F_x \), \( F_y \), and \( F_z \). The diagram provided gives a visual representation of the force \( \mathbf{F} \) and the angles involved.
#### Diagram Description:
- There is a 3-dimensional coordinate system (\( x \), \( y \), and \( z \) axes).
- Point \( A \) is where the force vector \( \mathbf{F} \) is applied.
- The vector \( \mathbf{F} \) makes an angle of 70° with the horizontal projection \( AB \) and an angle of 30° with the vertical plane.
- The horizontal projection \( AB \) extends 10 feet from the origin along the plane.
- The base \( B \) is 5 feet along the x-axis and 7 feet along the y-axis from the origin.
#### Possible Solution Choices:
1. \( F_x = -70.5 \); \( F_y = 57.2 \); \( F_z = -83.2 \)
2. \( F_x = 98.2 \); \( F_y = -44.7 \); \( F_z = -57.2 \)
3. \( F_x = -70.4 \); \( F_y = 88.2 \); \( F_z = -59.4 \)
4. \( F_x = 59.4 \); \( F_y = -88.2 \); \( F_z = -83.2 \)
#### Calculation Methodology:
To find the components \( F_x \), \( F_y \), and \( F_z \) of the force \( \mathbf{F} \), we can use trigonometric relationships from the angles provided. By projecting the force vector onto the coordinate axes and applying cosine and sine functions,
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