2. Express the force as a Cartesian vector in terms of unit vectors ‘i’ ‘j’ and ‘k’. Round to three significant figures
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- 6. Vector A has a magnitude of 5.00 units, and vector B has a magnitude of 9.00 units. The two vectors make an angle of 50.0° with cach other. Find A B. Note: In Problems 7 and 8, calculate numerical answers to three significant figures as usual. 7. Find the scalar product of the vectors in Figure P7.7. 118 32.8 N 132° 17.3 cm Figure P7.7 8. Using the definition of the scalar product, find the angles between (a) A = 3i-2j and B = 4i-4j. (b) A= -2i + 4j and B= 3i- 4j + 2k, and (c) A=i-2j + 2k and B = 3j + 4k. SECTION 7.4 Work Done by a Varying Force 9. A particle is subject to a force F that varies with position as shown in Figure P7.9. Find the work done by the force on the particle as it moves (a) from x = 0 to x = 5.00 m, (b) from x = 5.00 m to x = 10.0 m, and (c) from x= 10.0 m to x = 15.0 m. (d) What is the total work done by the force over the distance x= 0 tox= 15.0 m: 7, (N) X (m) 121 10 12 14 16 Figure P7.9 Problems 9 andl 22.4) Two vectors have equal magnitudes of 2.0 m. Find graphically the angle between them if the magnitude of their resultant is (a) 3.0 m; (b) 1.0 m. In each case use the law of cosines to confirm your answer. Problems 3 and 4 are graphical solutions. Please use a protractor, ruler, and compass and work as accurately as possible. Alternatively, you could use a vector drawing program to work out the geometrythe vector some of 80 N in the -x direction and 30 N at an angle of 53 with the +x axis is ...... N
- Three force vectors are added together. One has a magnitude of 9 N, the second one a magnitude of 18 N, and the third a magnitude of 15 N. What can we conclude about the magnitude of the net force vector? Explain. I. It must equal 42 N. II. It cannot be 0 N. III. Anything from –42 N to +42 N. IV. It can be anything from 0 N to 42 N. V. None of the above can be concluded.Can i get help with this problemOur vectors P and Q have the same amount. How can we rearrange them so that the sum of them is toward the right? Explain this?
- Given two vectors: M = -3î + 6j – 5k and N = -21 + 3j + k The magnitude of vector N is: A) 3.74 B) 8.37 70 D) 14 E) No AnswerYou are trying to push your stalled car. Although you apply a horizontal force of 400 N to the car, it doesn't budge, and neither do you. Which force(s) must also have a magnitude of 400 N? The friction force exerted by the road on you. The normal force exerted by the road on you. O The force exerted by the car on you. O The gravity force exerted by the car on the road.Which of the following statements about the vector product is or are true? I) The resulting vector is perpendicular to both input vectors. 8 - II) The vector product of a vector with itself is equal to the square of the magnitude of the vector. II) The unit vectors do obey the rules of the vector product. O A) I and III O B) I, II, and II O C) I and II D) II O E) Il and II
- 1. Let v = -51 + 53 be a vector in R². (a) Find v. (b) Find the angle, 0, in degrees, that v makes with the positive x-axis. (Answer in radians between 0 and 27.) (c) Find a unit vector that points in the same direction as v. Answer in component form.Please no hand writing solutionTwo vectors are given by A = 3 î + 6 ĵ and B = -1 î + ĵ. (a) Find A × B. k (b) Find the angle between A and B.