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The force exerted by Q₁(3.0m, 3.0m, 3.0m) = 1.0 μC on Q₂(6.0m, 9.0m, 3.0m) = 10. nC is equal to:
O a. F12 (1ax + 1.2ay) μN
O b.
F12 = (-1ax – 1.8ay) uN
O c.
F12
(0.89 ax + 1.8ay) μN

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