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The force exerted by Q₁(3.0m, 3.0m, 3.0m) = 1.0 μC on Q₂(6.0m, 9.0m, 3.0m) = 10. nC is equal to: O a. F12 (1ax + 1.2ay) µN O b. F12 = (-1ax – 1.8ay) UN O c. F12 (0.89 ax + 1.8ay) µN

The force exerted by Q₁(3.0m, 3.0m, 3.0m) = 1.0 μC on Q₂(6.0m, 9.0m, 3.0m) = 10. nC is equal to: O a. F12 (1ax + 1.2ay) µN O b. F12 = (-1ax – 1.8ay) UN O c. F12 (0.89 ax + 1.8ay) µN

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The force exerted by Q₁(3.0m, 3.0m, 3.0m) = 1.0 μC on Q₂(6.0m, 9.0m, 3.0m) = 10. nC is equal to: O a. F12 (1ax + 1.2ay) μN O b. F12 = (-1ax – 1.8ay) uN O c. F12 (0.89 ax + 1.8ay) μN
Transcribed Image Text:The force exerted by Q₁(3.0m, 3.0m, 3.0m) = 1.0 μC on Q₂(6.0m, 9.0m, 3.0m) = 10. nC is equal to: O a. F12 (1ax + 1.2ay) μN O b. F12 = (-1ax – 1.8ay) uN O c. F12 (0.89 ax + 1.8ay) μN
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