Your answer is partially correct. Try again.The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. Find the work doneby the force in the interval from (a) 0 to 0.7 m, (b) 1.0 to 2.0 m, and (c) 2.0 to 3.6 m. (Note: In the last interval the force componentis negative, so the work is negative.)T cos e+6.0 N2.0 m3.0 m4.0 m1.0 m-6.0 N(a) NumberUnit2.1(b) NumberUnit(c) Number-6.6Unit

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Description: Your answer is partially correct. Try again.The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. Find the work doneby the force in the interval from (a) 0 to 0.7 m, (b) 1.0 to 2.0 m, and (c

Component of the force at 0.7 m y=mx+c=y2-y1x2-x1x+c=6.0 N-0.0 N1.0 m-0.0 m0.7 m+0=4.2 N

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The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. Find the work dom by the force in the interval from (a) 0 to 0.7 m, (b) 1.0 to 2.0 m, and (c) 2.0 to 3.6 m. (Note: In the last interval the force componer is negative, so the work is negative.) F COs e 16.0 N-- 2.0 m 3.0 m 4.0 m 1.0 m -6.0 N (a) Number 2.1 Unit

The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. Find the work dom by the force in the interval from (a) 0 to 0.7 m, (b) 1.0 to 2.0 m, and (c) 2.0 to 3.6 m. (Note: In the last interval the force componer is negative, so the work is negative.) F COs e 16.0 N-- 2.0 m 3.0 m 4.0 m 1.0 m -6.0 N (a) Number 2.1 Unit

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Your answer is partially correct. Try again.
The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. Find the work done
by the force in the interval from (a) 0 to 0.7 m, (b) 1.0 to 2.0 m, and (c) 2.0 to 3.6 m. (Note: In the last interval the force component
is negative, so the work is negative.)
T cos e
+6.0 N
2.0 m
3.0 m
4.0 m
1.0 m
-6.0 N
(a) Number
Unit
2.1
(b) Number
Unit
(c) Number
-6.6
Unit

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