REMARKS The normal force n, the gravitational force m8, and the upward component of the appliedforce do no work on the sled because they're perpendicular to the displacement. The mass of the sleddidn't come into play here, but it is important when the effects of friction must be calculated and in thework-energy theorem.QUESTION How does the answer for the work done by the applied force change if the load is doubled?O The work is doubled.The work is halved.O The work is the same.Explain.

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QUESTION How does the answer for the work done by the applied force change if the load is doubled? O The work is doubled. The work is halved. The work is the same.

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Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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REMARKS The normal force n, the gravitational force m8, and the upward component of the applied
force do no work on the sled because they're perpendicular to the displacement. The mass of the sled
didn't come into play here, but it is important when the effects of friction must be calculated and in the
work-energy theorem.
QUESTION How does the answer for the work done by the applied force change if the load is doubled?
O The work is doubled.
The work is halved.
O The work is the same.
Explain.

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