The following table summarizes the financial data for a proposed new asset. The issue is how long the asset should be kept. Assume an interest rate of 12% anddelermine the economic service life of the anset.End of YearN)Investment costO&M CostSalvage value$14,000$3.400$8.000$4600$6.000$5.800$4,00001 yearO2 years3 yearsO Not enough information

Given Information : Year 0 1 2 3 Investment Cost $ (14,000.00) O&M cost $…

The following table summartzes the financial data for a proposed new asset. The issue is how long the anset should be kept. Assume an interest rate of 12% and determine the economic service ife of the asset. End of YearN Investment cost $14,000 Salvage value O&M Cost $3.400 $8.000 $6.000 $4.000 2. $4600 3. $5.800 01 year O2 years 3 yearn Not enough infortnation

The following table summartzes the financial data for a proposed new asset. The issue is how long the anset should be kept. Assume an interest rate of 12% and determine the economic service ife of the asset. End of YearN Investment cost $14,000 Salvage value O&M Cost $3.400 $8.000 $6.000 $4.000 2. $4600 3. $5.800 01 year O2 years 3 yearn Not enough infortnation

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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Similar questions

A project is estimated to cost P120T, last 8 years & have a salvage value of P20T. The annual gross income is expected to average P40k & annual expenses is P6T. If capital is earning 12% determine if this a desirable investment using rate of return, what is ROR. a. 20.07% b. 21.7% c. 19.77% d. 20.77%
The expected average rate of return for a proposed investment of $5,090,000 in a fixed asset, using straight-line depreciation, a useful life of 20 years, no residual value, and an expected total income of $10,180,000 over the 20 years, is (round to two decimal places) a.20.00% b.1.00% c.10.00% d.40.00%
Give me step by step solution and explanation
W:48)
Osler Company is considering an investment with the following data: Initial cost $200,000 Annual net cash inflows $25,000 Expected life 10 years Salvage value none Depreciation will be taken on a straight-line basis over the expected life of the investment.What is the accounting rate of return for the investment? a.12.5% b.2.5% c.20% d.25% e.10%
A project will produce an operating cash flow of $18,000 a year for 8 years. The initial fixed asset investment in the project will be $75,000. The net aftertax salvage value is estimated at $11,250 and will be received during the last year of the project's life. What is the IRR? A. 18.57% B. 16.71% C. 17.08% D. 18.94% E. 17.83%
Saved Help Save & Prairie Corporation has provided the following information for a proposed investment project: Discount rate 10% Life of the project 4 years Initial investment cost $23,775 Annual cost savings 7,500 Salvage value 1,500 What is the net present value of the proposed investment project? (Select the answer that is closest to your calculations.) Present value tables are provided below. Present Value of $1 Table (Exhibit 11B-1) (Partial table) Periods 4% 5% 6% 7% 8% 9% 10% 11% 12% 13% 14% 0.962 0.952 0.943 0.935 0.926 0.917 0.909 0.901 0.893 0.885 0.877 0.925 0.907 0.890 0.873 0.857 0.842 0.826 0.812 0.797 0.783 0.769 0.889 0.864 0.840 0.816 0.794 0.772 0.751 0.731 0.712 0.693 0.675 0.855 0.823 0.792 0.763 0.735 0.708 0.683 0.659 0.636 0.613 0.592 0.822 0.784 0.747 0.713 0.681 0.650 0.621 0.593 0.567 0.543 0.519 4. 0.790 0.746 0.705 0.666 0.630 0.596 0.564 0.535 0.507 0.480 0.456 0.760 0.711 0.665 0.623 0.583 0.547 0.513 0.482 0.452 0.425 0.400 0.731 0.677 0.627 0.582 0.540…
Consider two air-conditioning systems with the cash flow estimates as given below. Use AW analysis to determine the sensitivity of the economic decision to MARR values of 4%, 6%, and 8% per year. Air-Conditioning System 1 System First cost, $ AOC, $ per year Salvage value, $ New compressor and motor cost at midlife, $ Life, years -10,000 -500 -100 -1,850 8 The annual worth of air-conditioning system 1 when the MARR is 4% is $ The annual worth of air-conditioning system 2 when the MARR is 4% is $ The annual worth of air-conditioning system 1 when the MARR is 6% is $ The annual worth of air-conditioning system 2 when the MARR is 6% is $ The annual worth of air-conditioning system 1 when the MARR is 8% is $ The annual worth of air-conditioning system 2 when the MARR is 8% is $ Air-Conditioning System 2 -14,000 -85 -300 -2,540 12
Compare the alternatives C and D on the basis of a present worth analysis using an interest rate of 10% per year and a study period of 10 years. Alternative C First Cost $-40,000 $-11,000 $-24,000 AOC, per Year Annual Increase in Operating Cost, per Year Salvage Value Life, Years $-2,000 $-200 $-500 $6,000 $200 10 The present worth of alternative C is $ and that of alternative D is $ (Click to select) voffers the lower present worth.
please detail solution and explnation
Required information A company that manufactures magnetic flow meters expects to undertake a project that will have the cash flows estimated. First cost, $. Equipment replacement cost in year 2, $ Annual operating cost, $/year Salvage value, $ Life, years -870,000 -300,000 -920,000 250,000 4 At an interest rate of 10% per year, what is the equivalent annual cost of the project? Find the AW value using tabulated factors. The equivalent annual cost of the project is $-1
The cash flow of an energy management opportunity is estimated as follows: Initial cost:$12,000 Energy saving:$2,700/year for 12 years Maintenance cost:$1,200/year for 12 years Salvage value:$2,500@the end of 12 years If the interest rate is 10%, 1) What is the simple payback period (SPP) (in years)? (a)5.2 (b)4.2 (c)4.6 (d)8.02) With an annual discount rate is 10%, what is the discounted payback period (in years)? (a)9.5 b) 15.1 (c)8.1 (d) 16.9 (e) 6.53)With an annual discount rate is 10%, what is the benefit-cost ratio (BCR)? (Hint: Benefit = Annual saving-Maintenance; Cost= Initial investment - Salvage)(a) 1.04(b) 0.80(c) 1.25(d) 1.12(e) 1.43

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