The following table gives the mean velocity of planets in their orbits versus their mean distance from the sun. Note that 1 AU (astronomical unit) is the mean distance from Earth to the sun, about 93 million miles. Planet d = distance (AU) V = velocity (km/sec) Mercury Venus 0.39 47.4 0.72 35.0 Earth 1 29.8 Mars 1.52 24.1 Jupiter Saturn 5.20 13.1 9.58 9.7 Uranus 19.20 6.8 Neptune 30.05 5.4 Astronomers tell us that it is reasonable to model these data with a power function. (a) Use power regression to express velocity as a power function of distance from the sun. (Round regression parameters to two decimal places.) v= 21.41 x d-0.50 V = 21.41 x d-0.29 ov = 29.73 x d-0.50 v = 29.73 x d0.73 v = 29.73 x d0.50 (b) Plot the data along with the regression equation. 50 50 50 50 40 40 40 40 30 30 30 30 20 20 20 20 10 10 10 10 d 5 10 15 20 25 30 5 10 15 20 25 30 5 10 15 20 25 30 5 10 15 20 25 30 (c) An asteroid orbits at a mean distance of 3 AU from the sun. According to the power model you found in part (a), what is the mean orbital velocity of the asteroid? (Round your answer to two decimal places.) | km/sec

The following table gives the mean velocity of planets in their orbits versus their mean distance from the sun. Note that 1 AU (astronomical unit) is the mean distance from Earth to the sun, about 93 million miles. Planet d = distance (AU) V = velocity (km/sec) Mercury Venus 0.39 47.4 0.72 35.0 Earth 1 29.8 Mars 1.52 24.1 Jupiter Saturn 5.20 13.1 9.58 9.7 Uranus 19.20 6.8 Neptune 30.05 5.4 Astronomers tell us that it is reasonable to model these data with a power function. (a) Use power regression to express velocity as a power function of distance from the sun. (Round regression parameters to two decimal places.) v= 21.41 x d-0.50 V = 21.41 x d-0.29 ov = 29.73 x d-0.50 v = 29.73 x d0.73 v = 29.73 x d0.50 (b) Plot the data along with the regression equation. 50 50 50 50 40 40 40 40 30 30 30 30 20 20 20 20 10 10 10 10 d 5 10 15 20 25 30 5 10 15 20 25 30 5 10 15 20 25 30 5 10 15 20 25 30 (c) An asteroid orbits at a mean distance of 3 AU from the sun. According to the power model you found in part (a), what is the mean orbital velocity of the asteroid? (Round your answer to two decimal places.) | km/sec

Name: The following table gives the mean velocity of planets in their orbit
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Description: The following table gives the mean velocity of planets in their orbits versus their mean distance from the sun. Note that 1 AU (astronomical unit) is the mean distance from Earth to the sun, about 93 million miles.Planetd = distance (AU)v = velocity

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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