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The following reaction reaches equilibrium at the specified conditions. C6H5CH=CH2 (g) + H2 (g) <---> C6H5C2H5 (g) The system initially contains 3 mol H2 for each mole of styrene. Assume ideal gases. For styrene, ΔGof,298 = 213.18 kJ/mol, ΔHof,298 = 147.36 kJ/mol. (a) What is Ka at 600oC? (b) What are the equilibrium mole fractions at 600oC and 1 bar? (c) What are the equilibrium mole fractions at 600oC and 1 bar?

The following reaction reaches equilibrium at the specified conditions. C6H5CH=CH2 (g) + H2 (g) <---> C6H5C2H5 (g) The system initially contains 3 mol H2 for each mole of styrene. Assume ideal gases. For styrene, ΔGof,298 = 213.18 kJ/mol, ΔHof,298 = 147.36 kJ/mol. (a) What is Ka at 600oC? (b) What are the equilibrium mole fractions at 600oC and 1 bar? (c) What are the equilibrium mole fractions at 600oC and 1 bar?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The following reaction reaches equilibrium at the specified conditions.

C6H5CH=CH2 (g) + H2 (g) <---> C6H5C2H5 (g)

The system initially contains 3 mol H2 for each mole of styrene. Assume ideal gases. For styrene, ΔGof,298 = 213.18 kJ/mol, ΔHof,298 = 147.36 kJ/mol.

(a) What is Ka at 600oC?

(b) What are the equilibrium mole fractions at 600oC and 1 bar?

(c) What are the equilibrium mole fractions at 600oC and 1 bar?

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Can you please help me with solving these parts of this chemical engineering thermodynamics problem? Thank you!

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