The following reaction is known as the water- gas shift reaction: H2(g) + CO2(g) – – CO(g) + H20(g) for which Kc = 1.53 at a temperature of 686 •C. %3D a. Write an equation for Kc for this reaction in terms of the reactant and product concentrations. b. If you start with only 1.50 M of H20 and 1.50 M of CO, what will the equilibrium concentrations of all four substances be? Construct an ICE table and use the value for Кс above. c. What is the value of Kp for this reaction at 686 •C? d. If the reaction were at equilibrium and then CO2 was removed, in what direction would the reaction shift to recover equilibrium?

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Chapter1: Chemical Foundations
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The following reaction is known as the water-
gas shift reaction: H2(g) + CO2(g) – – CO(g)
+ H20(g) for which Kc = 1.53 at a temperature
of 686 •C.
a. Write an equation for Kc for this reaction in
terms of the reactant and product
concentrations.
b. If you start with only 1.50 M of H20 and
1.50 M of CO, what will the equilibrium
concentrations of all four substances be?
Construct an ICE table and use the value for
Кс above.
c. What is the value of Kp for this reaction at
686 •C?
d. If the reaction were at equilibrium and then
CO2 was removed, in what direction would the
reaction shift to recover equilibrium?
Transcribed Image Text:The following reaction is known as the water- gas shift reaction: H2(g) + CO2(g) – – CO(g) + H20(g) for which Kc = 1.53 at a temperature of 686 •C. a. Write an equation for Kc for this reaction in terms of the reactant and product concentrations. b. If you start with only 1.50 M of H20 and 1.50 M of CO, what will the equilibrium concentrations of all four substances be? Construct an ICE table and use the value for Кс above. c. What is the value of Kp for this reaction at 686 •C? d. If the reaction were at equilibrium and then CO2 was removed, in what direction would the reaction shift to recover equilibrium?
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