5. The production of ammonia from hydrogen and nitrogen has a Kp of 41. If the reaction what would Kc be? - 2 NH3(g) A. 41 B. 2.3 x 10-5 C. 24 N₂ (g) + 3 H₂ (g) D. 4.42 x 104 E. None of these run at 400 K 6. Consider the reaction A(g) + 2B(g) 4C(g) If the Kc for the reaction is 0.99 at 25 °C, what would be the Kp?

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**Transcription for Educational Website**

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**5. The production of ammonia from hydrogen and nitrogen has a \( K_p \) of 41. If the reaction is run at 400 K, what would \( K_c \) be?**

**Reaction:**  
\[ \text{N}_2\text{(g)} + 3 \text{H}_2\text{(g)} \rightleftharpoons 2 \text{NH}_3\text{(g)} \]

**Options:**  
A. 41  
B. \( 2.3 \times 10^{-5} \)  
C. 24  
D. \( 4.42 \times 10^4 \)  
E. None of these  

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**6. Consider the reaction \( \text{A(g)} + 2\text{B(g)} \rightleftharpoons 4\text{C(g)} \). If the \( K_c \) for the reaction is 0.99 at 25°C, what would be the \( K_p \)?**

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**Explanation of Concepts:**

- **\( K_p \) and \( K_c \):** \( K_p \) is the equilibrium constant for gaseous reactions based on partial pressures, whereas \( K_c \) is based on molar concentrations...
- **Effect of Temperature on Equilibrium:** Temperature can affect both \( K_p \) and \( K_c \), which are related by the equation:  
  \[ K_p = K_c(RT)^{\Delta n} \]  
  where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (moles of products - moles of reactants). 

Feel free to reach out for further explanation or guidance on these calculations.

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Transcribed Image Text:**Transcription for Educational Website** --- **5. The production of ammonia from hydrogen and nitrogen has a \( K_p \) of 41. If the reaction is run at 400 K, what would \( K_c \) be?** **Reaction:** \[ \text{N}_2\text{(g)} + 3 \text{H}_2\text{(g)} \rightleftharpoons 2 \text{NH}_3\text{(g)} \] **Options:** A. 41 B. \( 2.3 \times 10^{-5} \) C. 24 D. \( 4.42 \times 10^4 \) E. None of these --- **6. Consider the reaction \( \text{A(g)} + 2\text{B(g)} \rightleftharpoons 4\text{C(g)} \). If the \( K_c \) for the reaction is 0.99 at 25°C, what would be the \( K_p \)?** --- **Explanation of Concepts:** - **\( K_p \) and \( K_c \):** \( K_p \) is the equilibrium constant for gaseous reactions based on partial pressures, whereas \( K_c \) is based on molar concentrations... - **Effect of Temperature on Equilibrium:** Temperature can affect both \( K_p \) and \( K_c \), which are related by the equation: \[ K_p = K_c(RT)^{\Delta n} \] where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (moles of products - moles of reactants). Feel free to reach out for further explanation or guidance on these calculations. ---
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