5. The production of ammonia from hydrogen and nitrogen has a Kp of 41. If the reaction what would Kc be? - 2 NH3(g) A. 41 B. 2.3 x 10-5 C. 24 N₂ (g) + 3 H₂ (g) D. 4.42 x 104 E. None of these run at 400 K 6. Consider the reaction A(g) + 2B(g) 4C(g) If the Kc for the reaction is 0.99 at 25 °C, what would be the Kp?
5. The production of ammonia from hydrogen and nitrogen has a Kp of 41. If the reaction what would Kc be? - 2 NH3(g) A. 41 B. 2.3 x 10-5 C. 24 N₂ (g) + 3 H₂ (g) D. 4.42 x 104 E. None of these run at 400 K 6. Consider the reaction A(g) + 2B(g) 4C(g) If the Kc for the reaction is 0.99 at 25 °C, what would be the Kp?
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Transcription for Educational Website**
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**5. The production of ammonia from hydrogen and nitrogen has a \( K_p \) of 41. If the reaction is run at 400 K, what would \( K_c \) be?**
**Reaction:**
\[ \text{N}_2\text{(g)} + 3 \text{H}_2\text{(g)} \rightleftharpoons 2 \text{NH}_3\text{(g)} \]
**Options:**
A. 41
B. \( 2.3 \times 10^{-5} \)
C. 24
D. \( 4.42 \times 10^4 \)
E. None of these
---
**6. Consider the reaction \( \text{A(g)} + 2\text{B(g)} \rightleftharpoons 4\text{C(g)} \). If the \( K_c \) for the reaction is 0.99 at 25°C, what would be the \( K_p \)?**
---
**Explanation of Concepts:**
- **\( K_p \) and \( K_c \):** \( K_p \) is the equilibrium constant for gaseous reactions based on partial pressures, whereas \( K_c \) is based on molar concentrations...
- **Effect of Temperature on Equilibrium:** Temperature can affect both \( K_p \) and \( K_c \), which are related by the equation:
\[ K_p = K_c(RT)^{\Delta n} \]
where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (moles of products - moles of reactants).
Feel free to reach out for further explanation or guidance on these calculations.
---](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ac9d9fd-0ce6-4ad9-ac74-440cab402247%2F03b9828b-0285-427f-ac3a-d85c1004d3e4%2Fk86h2xo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
---
**5. The production of ammonia from hydrogen and nitrogen has a \( K_p \) of 41. If the reaction is run at 400 K, what would \( K_c \) be?**
**Reaction:**
\[ \text{N}_2\text{(g)} + 3 \text{H}_2\text{(g)} \rightleftharpoons 2 \text{NH}_3\text{(g)} \]
**Options:**
A. 41
B. \( 2.3 \times 10^{-5} \)
C. 24
D. \( 4.42 \times 10^4 \)
E. None of these
---
**6. Consider the reaction \( \text{A(g)} + 2\text{B(g)} \rightleftharpoons 4\text{C(g)} \). If the \( K_c \) for the reaction is 0.99 at 25°C, what would be the \( K_p \)?**
---
**Explanation of Concepts:**
- **\( K_p \) and \( K_c \):** \( K_p \) is the equilibrium constant for gaseous reactions based on partial pressures, whereas \( K_c \) is based on molar concentrations...
- **Effect of Temperature on Equilibrium:** Temperature can affect both \( K_p \) and \( K_c \), which are related by the equation:
\[ K_p = K_c(RT)^{\Delta n} \]
where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (moles of products - moles of reactants).
Feel free to reach out for further explanation or guidance on these calculations.
---
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