(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axis between a 0 and x = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p= Po 1 L2 where Po = 3.5 x 10 4. m. The end of the rod at a = 0 is at a potential V. 15 V greater than the end at a = L. A) What is the total resistance, in units of , of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer:
(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 4 m and cross-sectional area A = 3.5 mm2 lies along the x-axis between a 0 and x = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p= Po 1 L2 where Po = 3.5 x 10 4. m. The end of the rod at a = 0 is at a potential V. 15 V greater than the end at a = L. A) What is the total resistance, in units of , of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer:
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![(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
A rod of semiconducting material of length L = 4 m and cross-sectional area A
3.5 mm2 lies along the x-axis between a = 0
x2
where
L2
and x
L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po (1
Po = 3.5 x 10 4N· m. The end of the rod at x
O is at a potential Vo = 15 V greater than the end at a = L.
||
A) What is the total resistance, in units of 2, of the rod?
Answer:
B) What is the current, in units of miliamperes, in the rod?
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33568364-c303-44cc-a90d-f6a0576bc7fd%2F4a0e3abb-0a48-4104-be95-8332760f4c86%2F208yhi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
A rod of semiconducting material of length L = 4 m and cross-sectional area A
3.5 mm2 lies along the x-axis between a = 0
x2
where
L2
and x
L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po (1
Po = 3.5 x 10 4N· m. The end of the rod at x
O is at a potential Vo = 15 V greater than the end at a = L.
||
A) What is the total resistance, in units of 2, of the rod?
Answer:
B) What is the current, in units of miliamperes, in the rod?
Answer:
![C) What is the electric potential, in units of Volt, in the rod at x =L/2?
Answer:
D) What is the electric-field magnitude E, in units of V/m, in the rod at a = L/2?
Answer:
n](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33568364-c303-44cc-a90d-f6a0576bc7fd%2F4a0e3abb-0a48-4104-be95-8332760f4c86%2Fnmtklvn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:C) What is the electric potential, in units of Volt, in the rod at x =L/2?
Answer:
D) What is the electric-field magnitude E, in units of V/m, in the rod at a = L/2?
Answer:
n
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