The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi ✓in., given in increasing order)]: 65.3 71.9 72.8 73.1 73.4 73.5 75.5 75.7 75.8 76.1 76.2 76.2 77.0 77.9 78.1 79.6 79.7 79.9 80.1 82.2 83.5 93.6 Calculate a 99% CI for the standard deviation of the fracture toughness distribution. (Round your answers to one decimal place.) ksi vin Is this interval valid whatever the nature of the distribution? Explain. O The distribution needs to be skewed to the right.
The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi ✓in., given in increasing order)]: 65.3 71.9 72.8 73.1 73.4 73.5 75.5 75.7 75.8 76.1 76.2 76.2 77.0 77.9 78.1 79.6 79.7 79.9 80.1 82.2 83.5 93.6 Calculate a 99% CI for the standard deviation of the fracture toughness distribution. (Round your answers to one decimal place.) ksi vin Is this interval valid whatever the nature of the distribution? Explain. O The distribution needs to be skewed to the right.
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![The following observations were made on fracture toughness of a base plate of 18% nickel maraging
steel (in ksi ✓in., given in increasing order)]:
65.3 71.9 72.8 73.1 73.4 73.5 75.5 75.7 75.8 76.1 76.2
76.2 77.0 77.9 78.1 79.6 79.7 79.9 80.1 82.2 83.5 93.6
Calculate a 99% CI for the standard deviation of the fracture toughness distribution. (Round your
answers to one decimal place.)
ksi vin
Is this interval valid whatever the nature of the distribution? Explain.
O The distribution needs to be skewed to the right.
O The distribution needs to be approximately uniform.
O The interval is always valid.
The distribution needs to be approximately normal.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05306099-d17b-4786-a552-6aca0323abbc%2F4135f7a9-c1d5-4fba-9211-dd68798ec1d4%2F9npnyfp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following observations were made on fracture toughness of a base plate of 18% nickel maraging
steel (in ksi ✓in., given in increasing order)]:
65.3 71.9 72.8 73.1 73.4 73.5 75.5 75.7 75.8 76.1 76.2
76.2 77.0 77.9 78.1 79.6 79.7 79.9 80.1 82.2 83.5 93.6
Calculate a 99% CI for the standard deviation of the fracture toughness distribution. (Round your
answers to one decimal place.)
ksi vin
Is this interval valid whatever the nature of the distribution? Explain.
O The distribution needs to be skewed to the right.
O The distribution needs to be approximately uniform.
O The interval is always valid.
The distribution needs to be approximately normal.
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