I need help on all parts please **Identifying Outliers in a Data Set**The following numbers represent attendance at the last 11 screenings of a movie:195, 197, 199, 199, 200, 201, 203, 204, 205, 206, 209Complete the steps below to identify any outliers.**(a)** Let \( Q_1 \) be the lower quartile and \( Q_3 \) be the upper quartile of the data set. Find \( Q_1 \) and \( Q_3 \) for the data set.- \( Q_1 = \) [Text Box]- \( Q_3 = \) [Text Box]**(b)** Find the interquartile range (IQR) of the data set.- IQR = [Text Box]**(c)** Calculate a lower boundary using \( Q_1 - 1.5 \times \text{IQR} \). Calculate an upper boundary using \( Q_3 + 1.5 \times \text{IQR} \). (Note that \( 1.5 \times \text{IQR} \) means 1.5 times the IQR.)- Lower boundary: [Text Box]- Upper boundary: [Text Box]**(d)** Any values less than the lower boundary or greater than the upper boundary are considered outliers. Identify all the outliers of the data set. If more than one outlier is present, separate them with commas. If there are no outliers, click "None."- Outliers: [Text Box][Buttons: Explanation] [Check]

a) The total number of observations is n = 11.The observations are arranged in ascending order. That is, 195, 197, 199, 199, 200, 201, 203, 204, 205, 206, and 209. The 1st quartile is the [(n + 1)/4)]th observation, below which 25% of the observations lie. That is, for n = 11, the 1st quartile is, [(11 + 1)/4)]th observation = 3rd observation. The 3rd observation in ascending form is 199. Hence, the 1st quartile is Q1 = 199. The 3rd quartile is the [3(n + 1)/4)]th observation, below which 75% of the observations lie. That is, for n = 11, the 3rd quartile is, [3(11 + 1)/4)]th observation = 9th observation. The 9th observation in ascending form is 205. Hence, the 3rd quartile is Q3 = 205. b) The interquartile range is, IQR = Q3 – Q1 = 205 – 199 = 6. c) The lower boundary is, Q1 – 1.5(IQR) = 199 – (1.5)(6) = 190 The upper boundary is, Q3 + 1.5(IQR) = 205 + (1.5)(6) = 214 That is, Lower boundary :190 Upper boundary : 214 d) Any value less than the lower boundary of 190 or greater than the upper boundary of 214 is considered outlier. In this case, there are no such observations, that are less than the lower boundary of 190 or greater than the upper boundary of 214. Hence, there are no outliers. Outliers: None.