The following molecule (or ion) acts as a base: CH3 CH2O- Draw the structural formula of the conjugate acid formed in a reaction with HC • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered • Do not include counter-ions, e.g., Na*, I", in your answer. C P opy aste CH4
The following molecule (or ion) acts as a base: CH3 CH2O- Draw the structural formula of the conjugate acid formed in a reaction with HC • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered • Do not include counter-ions, e.g., Na*, I", in your answer. C P opy aste CH4
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:### Understanding Conjugate Acid-Base Reactions
The following educational content will guide you through the concept of conjugate acids by providing an example reaction involving a base, \( \text{CH}_3\text{CH}_2\text{O}^- \), and hydrochloric acid (HCl).
#### Prompt:
The given base is \( \text{CH}_3\text{CH}_2\text{O}^- \).
Your task is to draw the structural formula of the conjugate acid formed when this base reacts with hydrochloric acid (HCl).
#### Steps:
1. **Base Identification:**
- **Base**: \( \text{CH}_3\text{CH}_2\text{O}^- \)
- **Reacts With**: \( \text{HCl} \)
2. **Reaction Identification:**
- In a typical acid-base reaction, the base (\( \text{CH}_3\text{CH}_2\text{O}^- \)) will accept a proton (H\(^+\)) from the acid (\( \text{HCl} \)).
- The resultant molecule will be the conjugate acid, \( \text{CH}_3\text{CH}_2\text{OH} \).
#### Drawing Guidelines:
- **Explicit Hydrogen Atoms**: Not required to be drawn.
- **Lone Pairs**: Do not include them as they are not necessary for grading.
- **Counter-Ions (e.g., \( \text{Na}^+\), \( \text{I}^- \))**: Should not be included in your answer.
### Example Diagram:
The diagram for this exercise involves the use of a chemical drawing tool, **ChemDoodle**. The user is instructed to draw \( \text{CH}_3\text{CH}_2\text{OH} \) within the given drawing area.
#### Example:
The chemical drawing area in the diagram uses ChemDoodle tools such as:
- **Various Drawing Tools**: To create structures, including single, double, triple bonds, rings, and more.
- **Selection and Manipulation Tools**: To move and modify elements.
- **Toolbar Icons**: Representing different functionalities such as undo, redo, copy, paste, zoom, etc.
### Conclusion:
Understand the formation of the conjugate acid by drawing the resulting molecule from the given base when it
![## Completing the Equation Between Lewis Acid-Base Pairs
### Reaction Equation
\[ \text{H}_3\text{C} - \overset{+}{\text{C}} \text{H} - \text{CH}_3 + \text{Br}^- \rightarrow \]
### Instructions:
1. **Use the wedge/hash bond tools to indicate stereochemistry** where it exists.
2. **Draw only the reaction product.** If there is more than one product, draw all of them.
3. **Separate structures** with + signs from the drop-down menu.
4. **Draw cations and anions in separate sketchers.**
### Tools and Interface
Below is the interface where you can draw the reaction product:
- **ChemDoodle® Editor**: Use the provided drawing tools to accurately represent molecular structures.
- **Bond Tools**: Include single, double, triple bonds, and stereochemical indicators like wedges and hashes.
- **Functional Groups**: Access commonly used structures.
- **Templates**: Quickly draw complex ions and structures.
#### Diagram Description
The ChemDoodle® interface includes icons for tools such as:
- Hand tool for moving structures.
- Eraser tool for deleting parts of your drawing.
- Undo and redo buttons.
- Bond creation tools (single, double, triple, aromatic).
- Tools for drawing rings and other complex structures.
- Templates for common chemical structures.
The drawing area is black, providing a workspace for sketching the reaction product. Annotations can be added for clarity.
Use the drawer to illustrate the bond formation between the carbocation (\(\text{H}_3\text{C} - \overset{+}{\text{C}} \text{H} - \text{CH}_3\)) and the bromide anion (\(\text{Br}^-\)) to form the product.
Explore the tools to correctly draw and interpret the structures, ensuring precision in representing chemical reactions and stereochemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc0be470-4d83-48fd-a3a5-3890defc013a%2Ff2d2bc0f-6c83-423b-9bf4-2c09f3a17d86%2Fuldzbgk_processed.png&w=3840&q=75)
Transcribed Image Text:## Completing the Equation Between Lewis Acid-Base Pairs
### Reaction Equation
\[ \text{H}_3\text{C} - \overset{+}{\text{C}} \text{H} - \text{CH}_3 + \text{Br}^- \rightarrow \]
### Instructions:
1. **Use the wedge/hash bond tools to indicate stereochemistry** where it exists.
2. **Draw only the reaction product.** If there is more than one product, draw all of them.
3. **Separate structures** with + signs from the drop-down menu.
4. **Draw cations and anions in separate sketchers.**
### Tools and Interface
Below is the interface where you can draw the reaction product:
- **ChemDoodle® Editor**: Use the provided drawing tools to accurately represent molecular structures.
- **Bond Tools**: Include single, double, triple bonds, and stereochemical indicators like wedges and hashes.
- **Functional Groups**: Access commonly used structures.
- **Templates**: Quickly draw complex ions and structures.
#### Diagram Description
The ChemDoodle® interface includes icons for tools such as:
- Hand tool for moving structures.
- Eraser tool for deleting parts of your drawing.
- Undo and redo buttons.
- Bond creation tools (single, double, triple, aromatic).
- Tools for drawing rings and other complex structures.
- Templates for common chemical structures.
The drawing area is black, providing a workspace for sketching the reaction product. Annotations can be added for clarity.
Use the drawer to illustrate the bond formation between the carbocation (\(\text{H}_3\text{C} - \overset{+}{\text{C}} \text{H} - \text{CH}_3\)) and the bromide anion (\(\text{Br}^-\)) to form the product.
Explore the tools to correctly draw and interpret the structures, ensuring precision in representing chemical reactions and stereochemistry.
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