The following MINITAB output presents the results of a power calculation for a testconcerning a population proportion p.Power and Sample SizeTest for One ProportionTesting proportion =0.5 (versus not = 0.5)Alpha = 0.05AlternativeSample Size PowerProportion0.41500.691332Is the power calculated for a one-tailed or two-tailed test?a.b.What is the null hypothesis for which the power is calculated?C.For what alternative value of p is the power calculated?If the sample size were 100, would the power be less than 0.7, greater than 0.7, or is itimpossible to tell from the output? Explain.d.If the sample size were 200, would the power be less than 0.6, greater than 0.6, or is itimpossible to tell from the output? Explain.e.f.For a sample size of 150, is the power against the alternative p = 0.3 less than 0.65,greater than 0.65, or is it impossible to tell from the output? Explain.For a sample size of 150, is the power against the alternative p = 0.45 less than 0.65,greater than 0.65, or is it impossible to tell from the output? Explain.g.

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Answered: The following MINITAB output presents…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 ug/g. Assume that the sample is a simple random sample. 20.5 12.5 12.5 4.5 4.5 19 18 18.5 9. 16 O Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? Ο Α. Ηo μ> 16 μgg Ο Β. H μ= 16 μglg H1>16 ug/g H,: p< 16 pg/g O C. H μ= 16 μgg ΟD. Ho μ= 16 μgg H: p<16 ug/g H: p#16 pg/g
Answer these questions
a.)What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = b.)What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to four decimal places.)p-value =
The one-sample ?‑statistic for a test of ?0:?=0 versus ?1:?≠0 based on ?=15 observations has the value ?=−2.138, where ?0 and ?1 are the null and alternative hypotheses, respectively. The sample size is denoted by ?. Use this ?‑table to determine which two ?-values bracket the ?-value of the test. Report your answer as listed in the given ?‑table.
Given two independent random samples with the following results: n₁ = 651 x₁ = 307 n2 = 569 x2 = 234 Can it be concluded that there is a difference between the two population proportions? Use a significance level of a = 0.02 for the test. Copy Data Step 5 of 6: Determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion of your answer to two decimal places.
Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 18 µg/g. Assume that the sample is a simple random sample. 19 7.5 3 14 8 15 6 22.5 22.5 21.5 O Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? Ο Α. Η0: μ= 18 μαg Ο Β. Η μ= 18 μgg H1: µ> 18 µg/g H: µ# 18 µg/g OC. Ho: H= 18 µg/g Ο D. Ho: μ> 18 μgg H,: µ< 18 µg/g H,: µ< 18 µg/g Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. V Ho. There is V evidence to conclude that the mean lead concentration for all such medicines is 18 μgg. Reject Fail to reject
Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 ug/g. Assume that the sample is a simple random sample. 20.5 12.5 12.5 4.5 4.5 19 18 18.5 16 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho p> 16 pg/g H p 16 ug/g %3D O C. Ho p= 16 pg/g H p#16 pg/g D. Ho =16 pg/g H1:p<16 ug/g Determine the test statistic. - 1.42 (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.)
Which of the following statistical tools have independent samples? Chi-square Mann-Whitney Wilcoxon Paired t test
A sample of 42 observations is selected from one population with a population standard deviation of 4.5. The sample mean is 100.5. A sample of 56 observations is selected from a second population with a population standard deviation of 3.8. The sample mean is 98.5. Conduct the following test of hypothesis using the 0.10 significance level. H₂ H₁ H₂ H₁ H₁ H₂ a. Is this a one-tailed or a two-tailed test? O One-tailed test O Two-tailed test b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) The decision rule is to reject H0 if z is the interval (
A sample of 38 observations is selected from one population with a population standard deviation of 3.0. The sample mean is 100.5. A sample of 50 observations is selected from a second population with a population standard deviation of 5.2. The sample mean is 98.8. Conduct the following test of hypothesis using the 0.02 significance level. He: H₁ H₂ H₁ H₁ H₂ Required: a. Is this a one-talled or a two-talled test? O One-talled test Ⓒ Two-talled test b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) The decision rule is to reject Hō if z is > Answer is complete but not entirely correct. the interval ( outside 1.96 X c. Compute the value of the test statistic. (Round your answer to 2 decimal places.) 1.96 X

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