The following Is an Incomplete ANOVA table.df MS2 11.6Source of VariationFBetween groupsWithin groupsTotal150 10The p-value of the test IsMultiple Cholceless than 0.07between 0.01 and 0.031between 0.025 and 0.11greater than 0.10

The incomplete ANOVA table is given.

Answered: The following is an Incomplete ANOVA…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Nero Match Company sells matchboxes that are supposed to have an average of 40 matches per box, with o = 8. A random sample of 92 matchboxes shows the average number of matches per box to be 42.9. Using a 1% level of significance, can you say that the average number of matches per box is more than 40? What are we testing in this problem? O single mean O single proportion (a) What is the level of significance? State the null and alternate hypotheses. O Ho: H = 40; H1: H + 40 O Ho: p = 40; H: p > 40 O Ho: H = 40; H1: µ 40 (b) What sampling distribution will you use? What assumptions are you making? O The Student's t, since we assume that x has a normal distribution with unknown o. O The standard normal, since we assume that x has a normal distribution with unknown o. O The Student's t, since we assume that x has a normal distribution with known o. O The standard normal, since we assume that x has a normal distribution with known o. What is the value of the sample test statistic?…
The height of women ages 20-29 is normally distributed, with a mean of 63.6 inches. Assume o = 2.5 inches. Are you more lrely to randomly select 1 woman with a height less than 64.1 inches or are you more likely to select a sample of 20 women with a mean height less than 64.1 inches? Explain. E Click the icon to view page 1 of the standard normal table. E Click the icon to view page 2 of the standard normal table. What is the probability of randomly selecting 1 woman with a height less than 64.1 inches? (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Check Answer Clear All parts 2 Femaining
The p-value for a t-statistic was .008. What is the best way to report the level of significance? p<.008 p<.05 p<.01 p<.001
What are the degrees of freedom and critical values for independent samples t-tests with a = 0.05; two-tailed; n =10, n2= 10 %3D Please write your critical value answer in the following format: (for a 2 tailed test) 1.234 and-1.234 (for a one tailed test) 1.234 or -1.234
Use the following ANOVA table to answer the question. Source Regression Error Total MS SS 355.22 76.38 431.60 DF 177.61 7 10.91 What is the value of s?? O 177.61 10.91 76.38 335.05
What are the values for SS and variance for the following sample of n = 3 scores? Sample: 8, 5, 2
what is the value in cell D? Round to 2 decimal places. How many total observations were there in the study? Hint: use df(total) to figure out the number of total observations. The following computer output is for an analysis of variance in which yields (bu/acre) of different varieties of oats were compared. Answer the following questions based on this ANOVA table. Source df SS MS F ratio Prob Between groups 2 76.90 38.45 D 0.63 Within groups 11 859.81 78.16 Total 13 936.17
Is the racial distribution for students on work study different from the racial distribution for students not on work study? The results of a recent study are shown below. Frequencies of Race for Students On and Not On Work Study White Black Hispanic Asian Other Work Study 77 41 96 50 24 Not Work Study 70 79 86 73 30 α = 0.10 significance level The test-statistic for this data = (Please show your answer to three decimal places.) The p-value for this sample = (Please show your answer to four decimal places.) Thus, the final conclusion is... There is sufficient evidence to conclude that race and work study status are dependent. There is insufficient evidence to conclude that race and work study status are dependent. There is sufficient evidence to conclude that the racial distribution for students on work study is not the same as it is for students not on work study. There is insufficient evidence to conclude that the racial distribution for students on work study…
The height of women ages 20-29 is normally distributed, with a mean of 64.9 inches. Assume a = 2.5 inches. Are you more likely to randomly select 1 woman with a height less than 65.8 inches or are you more likely to select a sample of 29 women with a mean height less than 65.8 inches? Explain. E Click the icon to view page 1 of the standard normal table. E Click the icon to view page 2 of the standard normal table, What is the probability of randomly selecting 1 woman with a height less than 65.8 inches? O (Round to four decimal places as needed.)
Compute a one-way ANOVA on the following data using 0.05 significance level. Group A Group B Group C 14 11 14 13 12 12 10 13 13 12 13 12 14 ANOVA Source of Variation SS df MS F P-value F crit Between Groups ? ? ? ? ? Within Groups ? ? ? Total ? ?
Find the percentage of the total area under the standard normal curve between the following z-scores. z=1.44 and z=2.83 Click here for page 1 of the Areas under the Normal Curve Table Click here for page 2 of the Areas under the Normal Curve Table The percentage of the total area between z=1 44 and z=2.83 is% (Round to two decimal places as needed.)
Complete the one-way ANOVA output table below. Then interpret the results. Give MS- and F-values with 6 decimal places and S5-values with 5 decimal places. Source df MS P-value Treatment 2 79.86667 0.01030 Error 7.333333 Total 29 The P-value statistically significant, so there some difference between at least one pair of the three groups. is is not eTextbook and Media

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The following is an Incomplete ANOVA table. ss df MS 2 11.6 Source of Variation F Between groups Within groups Total 150 10 The p-value of the test is Multiple Choice less than 0.07 between 0.01 and 0.031 between 0.025 and O.1 greater than 0.10