please explain The following information is given for antimony at 1 atm:AHvap (1440.00°C) = 1.605 x 103 J/gAHtus ( 631.00°C) = 161.1 J/gT = 1440.00°CTm = 631.00°CSpecific heat solid = 0.2090 J/g °CSpecific heat liquid = 0.2590 J/g °CA 47.50 g sample of solid antimony is initially at 605.00°C. If 6.542 x 103 J of heat are added to the sample at constantpressure (P = 1 atm), which of the following is/are true?(Select all that apply.)| The sample is at a temperature greater than 631.00°C.| The sample is a liquid.The sample is a solid in equilibrium with liquid.O The sample is at a temperature of 631.00°C.The sample is a solid.

Given: Initial temperature of metal = 605.00 oC Amount of heat added = 6542 J And mass of metal =…

The following information is given for antimony at 1 atm: AHvap (1440.00°C) = 1.605 × 10° J/g AĦta ( 631.00°C) = 161.1 J/g T = 1440.00°C Tm = 631.00°C Specific heat solid = 0.2090 J/g °C Specific heat liquid = 0.2590 J/g °C A 47.50 g sample of solid antimony is initially at 605.00°C. If 6.542 x 10° J of heat are added to the sample at constant pressure (P = 1 atm), which of the following is are true? (Select all that apply.) | The sample is at a temperature greater than 631.00°C. | The sample is a liquid. O The sample is a solid in equilibrium with liquid. | The sample is at a temperature of 631.00°C. O The sample is a solid.

The following information is given for antimony at 1 atm: AHvap (1440.00°C) = 1.605 × 10° J/g AĦta ( 631.00°C) = 161.1 J/g T = 1440.00°C Tm = 631.00°C Specific heat solid = 0.2090 J/g °C Specific heat liquid = 0.2590 J/g °C A 47.50 g sample of solid antimony is initially at 605.00°C. If 6.542 x 10° J of heat are added to the sample at constant pressure (P = 1 atm), which of the following is are true? (Select all that apply.) | The sample is at a temperature greater than 631.00°C. | The sample is a liquid. O The sample is a solid in equilibrium with liquid. | The sample is at a temperature of 631.00°C. O The sample is a solid.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Compute for the isoelectric point of L-C-D-N-D-P-L-L Show a complete and detailed solution.
True or false if ring A was flipped it would result in ring B?
i) ОН MCPBA CH2Cl2 ОН H3PO4 heat D2O, D+
HOHHOHHOHHOHHO | || | ||||||||||||||| H₂N-C-C-N-C-C-N-C-C-N-C-C-N-C-C-O 1 I CH₂ 1 CH₂ CH3 CH₂ CH₂ I 1 OH 1 CH₂ CH-CH3 CH2 1 1 | C=O CH3 CH₂ 1 1 CH₂ NH₂ 1 NH3* (Blank 1) What is the common name of the N-terminal amino acid? (Blank 2) What is the 1-letter code of the C-terminal amino acid? (Blank 3) What is the classification of the peptide? (Blank 4) How many water is produced during the formation of the peptide above? (Encode the digit only.) (Blank 5) How many non-polar amino acids are present in the peptide? (Encode the digit only.) Blank # 1 N Blank # 2 Blank # 3 신
Conc. HNO, КОН
(a) dispersion force Dispersion forces are (Very weak),(Very strong) electrostatic attractions that occur due to the random electronic motion within all substances,(excluding),(including) those that are nonpolar. When the electrons within a molecule or atom are distributed asymmetrically about the nucleus, that molecule or atom will adopt a (temporary),(permanent), (induced),(instantaneous) dipole. The presence of this dipole can then distort the electrons of a neighboring atom or molecule, producing an (induced),(instantaneous) dipole. These two rapidly fluctuating dipoles thus result in a brief electrostatic (attraction),(Repulsion) between the two species. These forces are stronger in (Larger and heavier),(Smaller and lighter) atoms and molecules. For example, dispersion forces between (Fluorine),(iodine) molecules will be stronger than dispersion forces between (Fluorine),(iodine) molecules. (b) dipole-dipole attraction A dipole-dipole force is the electrostatic attraction…
Solve correctly please. Should 100% sure of final answer with some explanation of them.
Instructions: Determine and explain the type of intermolecular force of attraction that exists:
The second half is wrong. Please revaluate it
Show the mechanism
Please explain the R clockwise to S in your answer
Can the following substance (attached image) form hydrogen bonds with H2O? Please explain your method.