The following given is for questions 14 and 15: Consider a taut string of linear mass density u = 0.04 kg/m, stretched by a mass m as shown in the figure below. Vihrator The propagating wave produced by a vibrator on one end of the string is represented by the wave function: y(x, t) = 0.05 sin(3nx - 18nt + 4) where x and y are in meters and t is in seconds. 14) If at t 0, an element at x 0 has a vertical displacement y = -0.025 m and is moving upward, then the phase angle o is equal to: (a) n/6 rad (b) -n/6 rad (c) 5n/6 rad (d) 7n/6 rad 15) Suppose that the speed of this wave is v. In order to double its speed, the mass m suspended from the string should be multiplied by a factor of: (a) 0.25 (b)0.5 (c) 2 (d)4
The following given is for questions 14 and 15: Consider a taut string of linear mass density u = 0.04 kg/m, stretched by a mass m as shown in the figure below. Vihrator The propagating wave produced by a vibrator on one end of the string is represented by the wave function: y(x, t) = 0.05 sin(3nx - 18nt + 4) where x and y are in meters and t is in seconds. 14) If at t 0, an element at x 0 has a vertical displacement y = -0.025 m and is moving upward, then the phase angle o is equal to: (a) n/6 rad (b) -n/6 rad (c) 5n/6 rad (d) 7n/6 rad 15) Suppose that the speed of this wave is v. In order to double its speed, the mass m suspended from the string should be multiplied by a factor of: (a) 0.25 (b)0.5 (c) 2 (d)4
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Transcribed Image Text:The following given is for questions 14 and 15:
Consider a taut string of linear mass density u = 0.04 kg/m, stretched by a mass m as shown in the
figure below.
Vihrater
The propagating wave produced by a vibrator on one end of the string is represented by the wave
function:
y(x, t) = 0.05 sin(3nx – 18nt + p)
where x and y are in meters and t is in seconds.
14) If at t = 0, an element at x = 0 has a vertical displacement y = -0.025 m and is moving upward,
then the phase angle o is equal to:
(a) n/6 rad
(b) -7/6 rad
(c) 57/6 rad
(d) 7n/6 rad
15) Suppose that the speed of this wave is v. In order to double its speed, the mass m suspended
from the string should be multiplied by a factor of:
(a) 0.25
(b)0.5
(c) 2
(d)4
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