Consider a taut string of linear mass density µ = 0. 04 kg/m, stretched by a mass m as shown in the figure below. Vibrator The propagating wave produced by a vibrator on one end of the string is represented by the wave function: y(x, t) = 0. 05 sin(3nx 18nt + p) where xand y are in meters and t is in seconds. 14) f at t = 0, an element at x = 0 has a vertical displacement y = -0.025 m and is moving upward, then the phase angle ø is equal to:

University Physics Volume 1
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Chapter17: Sound
Section: Chapter Questions
Problem 105P: A string with a linear mass density of =0.0062 kg/m is stretched between two posts 1.30 m apart. The...
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Consider a taut string of linear mass density u = 0.04 kg/m, stretched by a mass m as shown in the
figure below.
Vibrator
The propagating wave produced by a vibrator on one end of the string is represented by the wave
function:
y(x, t) = 0.05 sin(3nx
18nt + p)
where xand y are in meters and t is in seconds.
14) fat t 0, an element at x = 0 has a vertical displacement y =
then the phase angle o is equal to:
0.025 m and is moving upward,
Transcribed Image Text:Consider a taut string of linear mass density u = 0.04 kg/m, stretched by a mass m as shown in the figure below. Vibrator The propagating wave produced by a vibrator on one end of the string is represented by the wave function: y(x, t) = 0.05 sin(3nx 18nt + p) where xand y are in meters and t is in seconds. 14) fat t 0, an element at x = 0 has a vertical displacement y = then the phase angle o is equal to: 0.025 m and is moving upward,
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