The following divider is used to divide 8ee by 2gen Diviser Shit right 64 bits Quotient 64-bil ALU Shit left 32 bits Remainder Control test Write 64 bits For simplicity, use 4 bits for the quotient and 8 bits for both divisor and remainder. What will be the initial values of quotient, divisor and remainder? a) 1000, 0010 0010, 0000 0000 0000, 0010 0000, 0000 1000 0010, 0000 0000, 0000 1000 b) d) 0000, 0000 0010, 0000 1000 e) 0000, 0010 0000, 1000 0000 0000, 1000 0000, 0010 0000 0000, 0000 1000, 0000 0010 h) None of the above What will be the values of quotient, divisor and remainder after the fourth iteration of the division algorithmlafter iteration 4) a) 0000, 0000 0010,0000 0010 b) 0001. 0010 0000, 0000 0000 0100, 0000 0100, 0000 0100 d) 0010, 0000 0010, 0000 0000 0000, 0000 0001.0000 0000 e) 1) 0001. 0000 0010, 0010 0000

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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२चप
The following divider is used to divide 8ten by 2ten:
Divisor
Shift right
64 bits
Quotient
64-bit ALU
Shift left
32 bits
Remainder
Control
Write
test
64 bits
For simplicity, use 4 bits for the
otient and 8 bits for both divisor and remainder.
What will be the initial values of quotient, divisor and remainder?
1000, 0010 0010, 0000 0000
a)
0000, 0010 0000, 0000 1000
b)
c)
0010, 0000 0000, 0000 1000
d)
0000, 0000 0010, 0000 1000
e)
0000, 0010 0000, 1000 0000
f)
0000, 1000 0000, 0010 0000
g)
0000, 0000 1000, 0000 0010
h)
None of the above
What will be the values of quotient, divisor and remainder after the fourth iteration of the division algorithm?(after iteration 4)
a)
0000, 0000 0010, 0000 0010
b)
0001, 0010 0000, 0000 0000
0100, 0000 0100, 0000 0100
c)
0010, 0000 0010, 0000 0000
d)
e)
0000, 00000001, 0000 0000
f)
0001, 0000 0010, 0010 0000
g)
0010, 0000 0100, 0000 0000
h)
None of the above
Transcribed Image Text:२चप The following divider is used to divide 8ten by 2ten: Divisor Shift right 64 bits Quotient 64-bit ALU Shift left 32 bits Remainder Control Write test 64 bits For simplicity, use 4 bits for the otient and 8 bits for both divisor and remainder. What will be the initial values of quotient, divisor and remainder? 1000, 0010 0010, 0000 0000 a) 0000, 0010 0000, 0000 1000 b) c) 0010, 0000 0000, 0000 1000 d) 0000, 0000 0010, 0000 1000 e) 0000, 0010 0000, 1000 0000 f) 0000, 1000 0000, 0010 0000 g) 0000, 0000 1000, 0000 0010 h) None of the above What will be the values of quotient, divisor and remainder after the fourth iteration of the division algorithm?(after iteration 4) a) 0000, 0000 0010, 0000 0010 b) 0001, 0010 0000, 0000 0000 0100, 0000 0100, 0000 0100 c) 0010, 0000 0010, 0000 0000 d) e) 0000, 00000001, 0000 0000 f) 0001, 0000 0010, 0010 0000 g) 0010, 0000 0100, 0000 0000 h) None of the above
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