The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = silicate, 3 = magnetite, 4 = hematite). 1: 20.3 28.1 27.8 27.0 27.5 25.2 25.3 27.1 20.5 31.2 2: 26.1 24.0 26.2 20.2 23.9 34.0 17.1 26.8 23.7 24.8 3: 30.2 34.0 27.5 29.4 28.4 26.2 29.9 29.5 30.0 36.1 4: 36.3 44.2 34.1 30.3 32.0 33.1 34.1 32.9 36.3 25.3 Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. H0: ?1 = ?2 = ?3 = ?4 Ha: all four ?i's are unequal H0: ?1 = ?2 = ?3 = ?4 Ha: at least two ?i's are unequal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4 Ha: all four ?i's are equal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4 Ha: at least two ?i's are equal Summarize the results in an ANOVA table. (Round your answers two decimal places.) Source df Sum of Squares Mean Squares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? P-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 P-value < 0.001 State the conclusion in the problem context. Fail to reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Fail to reject H0. There is sufficient evidence to
The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = silicate, 3 = magnetite, 4 = hematite). 1: 20.3 28.1 27.8 27.0 27.5 25.2 25.3 27.1 20.5 31.2 2: 26.1 24.0 26.2 20.2 23.9 34.0 17.1 26.8 23.7 24.8 3: 30.2 34.0 27.5 29.4 28.4 26.2 29.9 29.5 30.0 36.1 4: 36.3 44.2 34.1 30.3 32.0 33.1 34.1 32.9 36.3 25.3 Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses. H0: ?1 = ?2 = ?3 = ?4 Ha: all four ?i's are unequal H0: ?1 = ?2 = ?3 = ?4 Ha: at least two ?i's are unequal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4 Ha: all four ?i's are equal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4 Ha: at least two ?i's are equal Summarize the results in an ANOVA table. (Round your answers two decimal places.) Source df Sum of Squares Mean Squares f Treatments Error Total Give the test statistic. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? P-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 P-value < 0.001 State the conclusion in the problem context. Fail to reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Fail to reject H0. There is sufficient evidence to
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The following data was reported on total Fe for four types of iron formation (1 = carbonate, 2 = silicate, 3 = magnetite, 4 = hematite).
1: | 20.3 | 28.1 | 27.8 | 27.0 | 27.5 | 25.2 | 25.3 | 27.1 | 20.5 | 31.2 |
2: | 26.1 | 24.0 | 26.2 | 20.2 | 23.9 | 34.0 | 17.1 | 26.8 | 23.7 | 24.8 |
3: | 30.2 | 34.0 | 27.5 | 29.4 | 28.4 | 26.2 | 29.9 | 29.5 | 30.0 | 36.1 |
4: | 36.3 | 44.2 | 34.1 | 30.3 | 32.0 | 33.1 | 34.1 | 32.9 | 36.3 | 25.3 |
Carry out an analysis of variance F test at significance level 0.01. State the appropriate hypotheses.
H0: ?1 = ?2 = ?3 = ?4
Ha: all four ?i's are unequal H0: ?1 = ?2 = ?3 = ?4
Ha: at least two ?i's are unequal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4
Ha: all four ?i's are equal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4
Ha: at least two ?i's are equal
Ha: all four ?i's are unequal H0: ?1 = ?2 = ?3 = ?4
Ha: at least two ?i's are unequal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4
Ha: all four ?i's are equal H0: ?1 ≠ ?2 ≠ ?3 ≠ ?4
Ha: at least two ?i's are equal
Summarize the results in an ANOVA table. (Round your answers two decimal places.)
Source | df | Sum of Squares |
Mean Squares |
f |
---|---|---|---|---|
Treatments | ||||
Error | ||||
Total |
Give the test statistic. (Round your answer to two decimal places.)
f =
What can be said about the P-value for the test?
P-value > 0.100 0.050 < P-value < 0.100 0.010 < P-value < 0.050 0.001 < P-value < 0.010 P-value < 0.001
State the conclusion in the problem context.
Fail to reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Reject H0. There is insufficient evidence to conclude that the total Fe differs for the four formations. Fail to reject H0. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations. Reject H0. There is sufficient evidence to conclude that the total Fe differs for at least two of the four formations.
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