The following data give the constant dissociation, Ka (for acetic acid at various temperatures): T(°C) 0 Ка 1.657 x 10-5 10 1.729 x 10-5 15 1.745 x 10-5 25 1.753 × 10-5 kJ ΔΗ° = 1.53 mol Submit Previous Answers Part B Correct Plot Inka vs. 1/T and fit a line to the points. The slope will correspond to —▲H° / R. 1/T InKa 3.66 x 10-3-11.01 3.53 x 10-3-10.97 3.47 x 10-3-10.96 3.36 × 10-3-10.95 InKa = (−184 K) (±) — 10.3 = slope -184 K = AH° R AH° -184 K = 0.008314 kJ/(mol·K) AH 1.53 kJ/mol = Use these data, and the constant dissociation at 25 °C, to calculate AS° for acetic acid ionization. (InK Express your answer with the appropriate units. μÅ AS° = Value Units ? -AH° + ᎡᎢ. AS° R

What is the isoelectric point of HPY?

Predict the diffusivity of human serum albumin at 293 K in water as a dilute solution and compare it with experimental data. Assume the following: The molecular weight of human serum albumin, MA= 72,300 kg/kmol The viscosity of water at 293 K is 0.897 x 10-3 Pa∙s The experimental data value is 5.93 x 10-11 m2/s.

Consider the following equilibrium at 298 K. R = 8.314 J/K-mol Citrate Isocitrate Using the equilibrium concentrations of [Citrate] = 2.15 M and [Isocitrate] = 0.00825 M, calculate K'g, then AG°. Which one of the following is the correct value for AG in units of kJ/mol? 5990 kJ/mol -2480 kJ/mol 2.48 kJ/mol 13.8 kJ/mol 5.99 kJ/mol -2.48 kJ/mol -5990 kJ/mol -9.99 kJ/mol -13800 kJ/mol 13800 kJ/mol -5.99 kJ/mol 9.99 kJ/mol 2480 kJ/mol 9990 kJ/mol -13.8 kJ/mol -9990 kJ/mol O O O O O O O O O O0000 O O

The isoelectric point of eIF4a is 5.02. Students are given a sample of cell lysate containing eIF4A at pH 7.4. They are also provided with two buffers of pH 7.4 to use for ion exchange chromatography. One buffer has a very high salt concentration (1 M), the other has a low salt concentration (0.1 M). Mariela decides to use an anion exchange column, while Ashok chooses a cation exchange column. Who made the better decision? Provide a detailed explanation of why one student will end up with a purer sample of eIF4A.    Which buffer will you use while washing away impurities (high or low salt), and which would you use to remove eIF4A from the column? Explain your choice.

The main constituents in vinegar are water and ethanoic acid (CH3COOH). In order to determine the concentration of acid in homemade vinegar, a student titrated 25 cm3 of 001 M NaOH against the vinegar. The equation for the reaction is:                                     CH3COOH(aq) + NaOH(aq) ® CH3COONa(aq) + H2O(l)   The following titration results were obtained:   Burette readings (cm3) Rough 1 2 Final burette reading 20.10 38.90 31.40 Initial burette reading   0.10 20.00 12.50 Volume of vinegar used 20.00 18.90 18.90   (a) What volume of vinegar should be used in the calculation?                                           (b) What is the mole ratio of NaOH:CH3COOH?                                                              (c)  Calculate the number of moles of alkali in 25 cm3 of NaOH solution used.               (d) How many moles of acid were used in the titration?                                                    (e) Calculate the…

After three minutes, the concentration of drug Zip in the red blood cells is 10 mmoles l-1. What is the average rate of entry of drug Zip into the red blood cells in units of moles min-1 red blood cell-1 during the first three minutes after placing the red blood cells into the bathing solution? Assume that each red blood cell occupies about 1 x 10-13 liters.

A 100 ml of a 1% sol'n of boric acid (freezing point = -0.29) isotonic w/ blood by NaCl (freezing point = -0.58). what grams is needed to make it an isotonic?  what weight of NaCl is needed to a 2% sol'n of atropine sulfate (E=0.13) made isotonic with blood plasma?

Concanavalin (ConA) is a 25.5KDa protein with pl of 4.7 and optical absorbance (A 0.1% 289) of 1.14. calculate the concentration of an aqueous solution of pure BSA protein with an absorbance of 0.66 at 280nm. give your answer in units of mg/ml ?

at 257 nm) is dissolved in 2.5 mL of buffer. A 250 microliter aliquot is removed and placed in a 1.0 cm A sample of adenosine triphosphate (ATP) (MW 507, ɛ = 14,700 M'cm cuvette with sufficient buffer to give a total volume of 2.0 mL. The absorbance of the sample at 257 nm is 2.0. Calculate the weight of ATP in the original 2.5 mL sample. (Choose the correct value from the drop-down list provided. The values of weight are listed in units of milligrams.) Weight of ATP: v mg