The following data are the Medical Expenses in each of the 50 states. Using descriptive statistics, measures of central tendency, and measures of dispersion, answer the following questions below. The data is in thousands of dollars and is arranged in alphabetical order Q 1: Determine the Relative Frequency of the fourth class Write the result as follows (0 .XX) Q 2: Determine the Relative Frequency of the fifth class. Write the result as follows (0 .XX) Q 3: Determine the Cumulative Relative Frequency of the fifth class. Write the result as follows (0 .XX)

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The following data are the Medical Expenses in each of the 50 states.
Using descriptive statistics, measures of central tendency, and measures of dispersion, answer the following questions below.
The data is in thousands of dollars and is arranged in alphabetical order

Q 1: Determine the Relative Frequency of the fourth class Write the result as follows (0 .XX)

Q 2: Determine the Relative Frequency of the fifth class. Write the result as follows (0 .XX)

Q 3: Determine the Cumulative Relative Frequency of the fifth class. Write the result as follows (0 .XX)

Q 4: The value (Bar Height) of the Histogram of the last class is

Q 5: The value of the Polygon of the fifth class in percent is:
Write the number only, do not use symbols

Q 6: The value of the Warhead of the fifth class in percent is
Write the number only, do not use symbols

Q 7: Determine the average (Average) of the data. Write the result as follows (XXX .X)

Q 8: Find the median of the data. Write the result as follows (XXX .X)

Q 9: Determine the mode of the data

Q 10: Determine the standard deviation of the data. Write the result as follows (XXX .X)

Q 11: Determine the amount of medical expenses of the first class. Use numbers only do not use symbols

Q 12: From the previous answer. Find the standard deviation of the first class medical expenses. Write the result as follows (XX .X)

AL $775
НI 823
MA1,036
NM1,046
SD 506
AK 1,136
ID 659
MI 902
NY 784
TN 859
AZ 1,091
IL 917
MN 652
NC 763
TX1,010
AR 678
IN 898
MS 555
ND 507
UT1,081
мо 863
ут 676
он 940
ок 797
CA 1,221
IA 612
со 961
ст 1058
KS 666
мT 482
VA 830
KY 703
NE 626
OR 1,052
WA 1,143
WV 701
WI 744
DE 1,024
LA 875
NV 900
PA 861
FL
960
ME 738
NH 976
RI
885
GA 775
MD 889
NJ
829
SC
838
WY 537
Transcribed Image Text:AL $775 НI 823 MA1,036 NM1,046 SD 506 AK 1,136 ID 659 MI 902 NY 784 TN 859 AZ 1,091 IL 917 MN 652 NC 763 TX1,010 AR 678 IN 898 MS 555 ND 507 UT1,081 мо 863 ут 676 он 940 ок 797 CA 1,221 IA 612 со 961 ст 1058 KS 666 мT 482 VA 830 KY 703 NE 626 OR 1,052 WA 1,143 WV 701 WI 744 DE 1,024 LA 875 NV 900 PA 861 FL 960 ME 738 NH 976 RI 885 GA 775 MD 889 NJ 829 SC 838 WY 537
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(1). Determine the relative frequency of the fourth class:

Frequency distribution:

The number of values lying in the particular interval or the number of times each value repeats is the frequency of that particular class interval or event. The frequencies are calculated by using the tally mark.

The data represents the medical expenses in each of the 50 states.

The data has to be arranged in ascending order.

The minimum and maximum values of the dataset are 482 and 1221.

Here, the number of data values that falls under the specified interval is the frequency of that particular class interval.

Procedure for constructing the frequency distribution:

Step by step procedure for constructing the frequency distribution is given below:

  • The first lower bound should be the minimum value or a number smaller than the minimum value of the variable “medical expenses”. That is, the first lower bound should be 482 (or) less.
  • The number of values of medical expenses falls under the specified interval is the frequency of that particular class interval of medical expenses.
  • Find the class width as (maximum value – minimum value)/ number of classes.
  • Add the class width to the lower limit of the first class to get lower limit of the second class. Keep on doing this until the lower limit of the last class is obtained.
  • Now, subtract 1 from class width and add the result to the lower limit of the first class to get upper limit of the first class. Continue the same procedure to find upper limits of all class.

The number of classes is obtained as given below:

Statistics homework question answer, step 1, image 1

Thus, the number of classes is 6.

The class width is obtained as given below:

Statistics homework question answer, step 1, image 2

Thus, the class width is 131.

Consider the first lowest class interval as 482.

Hence, the lower limits of the class intervals with minimum value as first lower limit are: 482, 613, 744, 875, 1006, 1137. and the upper limits of the class intervals are obtained by adding 130 to lower limits as: 612, 743, 874, 1005, 1136 and 1267.

The number of values in between the class interval 482 -612 is 6.

Therefore, the frequency of the class interval 482 -612 is 6.

Similarly, the frequencies of all the remaining class intervals have to be calculated.

The frequency distribution for the dataset of medical expenses is obtained from the calculation given below:

Statistics homework question answer, step 1, image 3

The relative frequency of the fourth class is obtained as given below:

Statistics homework question answer, step 1, image 4

Thus, the relative frequency of the fourth class is 0.22.

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