### Calculating the Solubility Product Constant (Ksp)The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate \( K_{sp} \) for each of the slightly soluble solids indicated:a. **Silver Bromide (AgBr):** \([\text{Ag}^+]\) = \(5.7 \times 10^{-7}\) M, \([\text{Br}^-]\) = \(5.7 \times 10^{-7}\) Mb. **Calcium Carbonate (CaCO₃):** \([\text{Ca}^{2+}]\) = \(5.3 \times 10^{-3}\) M, \([\text{CO}_3^{2-}]\) = \(9.0 \times 10^{-7}\) Mc. **Lead(II) Fluoride (PbF₂):** \([\text{Pb}^{2+}]\) = \(2.1 \times 10^{-3}\) M, \([\text{F}^-]\) = \(4.2 \times 10^{-3}\) M#### Explanation:In order to calculate the solubility product constant (\( K_{sp} \)), we use the concentrations of the ions at equilibrium. The general formula for the solubility product constant is:\[ K_{sp} = [\text{Cation}^{n+}] [\text{Anion}^{m-}] \]Where \([\text{Cation}^{n+}]\) and \([\text{Anion}^{m-}]\) are the molar concentrations of the ions in solution.For the given compounds:**a. AgBr**\[ K_{sp} = [\text{Ag}^+][\text{Br}^-] \]**b. CaCO₃**\[ K_{sp} = [\text{Ca}^{2+}][\text{CO}_3^{2-}] \]**c. PbF₂**\[ K_{sp} = [\text{Pb}^{2+}][\text{F}^-]^2 \]Note that for PbF₂, the fluoride ion concentration is squared because each formula unit of PbF₂ produces two fluoride ions.

If AmBn is slightly soluble solid then Ksp can be written as - AmBn. -------> mAn+ + nBm- Ksp =…

The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate Ksp for each of the slightly soluble solids indicated: a. AgBr:[Ag*] = 5.7 × 10-7 M, [Br]= 5.7 × 10-7M b. CaCO3: [Ca²+] = 5.3 × 10-³M, [CO3²¯] = 9.0 × 10-7M c. PbF₂: [Pb²+] = 2.1 × 10-³ M, [F] = 4.2 × 10-³ M

The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate Ksp for each of the slightly soluble solids indicated: a. AgBr:[Ag*] = 5.7 × 10-7 M, [Br]= 5.7 × 10-7M b. CaCO3: [Ca²+] = 5.3 × 10-³M, [CO3²¯] = 9.0 × 10-7M c. PbF₂: [Pb²+] = 2.1 × 10-³ M, [F] = 4.2 × 10-³ M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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