NaCl (s) ⇌ Na+(aq) + Cl-(aq) When adding 6M HCl, the solid white precipitate is observed. When adding 0.1M HCl, no change is observed, no solid white precipitate is observed in the NaCl solution. Explain the similarities and differences by using Le Chatlier's principle.

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NaCl (s) ⇌ Na+(aq) + Cl-(aq)

When adding 6M HCl, the solid white precipitate is observed.

When adding 0.1M HCl, no change is observed, no solid white precipitate is observed in the NaCl solution.

Explain the similarities and differences by using Le Chatlier's principle. 

Expert Solution
Step 1

When a ionic solute is dissolved in a solvent, the solute gets dissociated into ions in the solution. There will be an equilibrium existing between the dissolved ions  and undissolved molecules.

The equilibrium constant of the dissolved ions in the solution is called the solubility product constant (Ksp). It is the product of the equilibrium concentration of the ions or the concentration of the ions in a saturated solution raised to the power of their dissolution reaction coefficient.

Here, the solution is made from the ionic solute NaCl dissolved in water. Therefore, the NaCl exists as Na+ and Cl- ions. 

The dissolution of NaCl can be written as follows.

NaCl (s)Na+(aq) +Cl-(aq)  

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