The following are prices of a sanitizer sold at a few selected stores in a District A during the COVID-19 pandemic. Based on the sample data, at 0.05 level of significance, can we conclude the average price of the sanitizer in District A is RM10.50? Make your conclusion using the p-value approach, with the aid of Mic. Office EXCEL.

The following are prices of a sanitizer sold at a few selected stores in a District A during the COVID-19 pandemic. Based on the sample data, at 0.05 level of significance, can we conclude the average price of the sanitizer in District A is RM10.50? Make your conclusion using the p-value approach, with the aid of Mic. Office EXCEL.

Name: The following are prices of a sanitizer sold at a few selected stores
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: The following are prices of a sanitizer sold at a few selected stores in a District A during theCOVID-19 pandemic. Based on the sample data, at 0.05 level of significance, can weconclude the average price of the sanitizer in District A is RM10.50? M

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Women are recommended to consume 1720 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1837, 1618, 1820, 1846, 1640, 1700, 1655, 1473, 1563, 1840, 1796, 1854 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = H1:H1: ? p μ Select an answer ≠ = < > The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean…
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.16, y = 102.3, r= 0.810, P-value = 0.000, and y = 23.09+0.78x, where x represents the IQ score of the wife. Find the best %3D %3D %3D predicted value of y given that the wife has an IQ of 109? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. .... The best predicted value of y is . (Round to two decimal places as needed.) Critical values of the pearson correlation coefficient r NOTE: To test Ho: p = 0 against H,: p#0, reject Ho |if the absolute value of r is greater than the critical value in the table. a = 0.05 a = 0.01 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40…
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
In a multiple regression analysis, two independent variables are considered and the sample size is 26. The regression coefficients and the standard errors are as follows; b1 = 1.468 sb1 = 0.89 b2 = -1.084 sb2 = 0.88 Use the 0.05 significance level; Conduct a test hypothesis to determine whether either independent variable has a coefficient equal to 0. (negative amounts should be indicated by a minus sign) (round to 3 decimal places) Would you consider deleting either variable from the regression equation? *See image
The old variety of a plant has 70% pink flowers. A new variety is developed. In a random sample of 93 plants from the new variety, 59 had pink flowers. Test the claim that the percent of plants with pink flowers for the new variety is different than 70%. Use a 0.10 level of significance. Question 6 options: DO NOT Reject H0 Using a 0.10 level of significance there is not evidence to say the proportion of pink flowers is different than 0.70 Reject H0 Using a 0.10 level of significance there is evidence to say the proportion of pink flowers is not different than 0.70
Suppose data is collected to predict y from x. If the size of Sample ✓ Calculate the p-value if the test statistic is t = -1.38
a study of store checkout scanners, 1234 items were checked and 23 checked items were overcharges. Use a 0.05 significance level to test the claim that with scanners, 1% of sales are overchanrges. (Before scanners were used, the overcharge rate was estimated to be about 1%). a. Define the parameter A. mu = The proportion of all sales that are undercharges B. p = The proportion of all sales that are incorrect C. p = The proportion of all sales that are overcharges D. mu = The mean number of sales that are overcharges b. State the null and alternative hypotheses A. Upper H 0 : mu not equals 0.01 Upper H 1 : mu equals 0.01 B. Upper H 0 : p greater than 0.01 Upper H 1 : p equals 0.01 C. Upper H 0 : p equals 0.01 Upper H 1 : p not equals 0.01 D. Upper H 0 : p equals 23 Upper H 1 : p less than 23 c. Calculate the sample proportion ModifyingAbove p…
A researcher decides to measure anxiety in group of bullies and a group of bystanders using a 23-item, 3 point anxiety scale. Assume scores on the anxiety scales are normally distributed and the variance among the group of bullies and bystanders are the same. A group of 30 bullies scores an average of 21.5 with a sample standard deviation of 10 on the anxiety scale. A group of 27 bystanders scored an average of 25.8 with a sample standard deviation of 8 on the anxiety scale. You do not have any presupposed assumptions whether bullies or bystanders will be more anxious so you formulate the null and alternative hypothesis based on that.
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…
Women are recommended to consume 1700 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1808, 1681, 1723, 1847, 1808, 1858, 1461, 1449, 1631, 1635, 1815, 1874 Assuming that the distribution is normal, what can be concluded at the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 1700 at αα = 0.01, so there is sufficient evidence to conclude that the population mean calorie intake for women at your college is equal to 1700. The data…
Provide an appropriate response. Test the hypothesis that p1 = P2. Use a = 0.05. The sample statistics listed below are from independent samples. Sample statistics: n1 = 50, x1 35, and n2 = 60, x2 = 40 Step 1) State the null and alternative hypotheses. Step 2) Determine the critical value for the level of significance, a. Step 3) Find the test statistic or P-value. Step 4) Will the researcher reject the null hypothesis or do not the null hypothesis: Step 5) Write the conclusion. HTML Editor BIUA A、IE三= Ex x E 曲。 12pt Pa SAMSUNG 10
A study was conducted of 90 adult male patients following a new treatment for congestive heart failure. One of the variables measured on the patients was the increase in exercise capacity (in minutes) over a 4-week treatment The previous treatment regime had produced an average increase of μ = 2 minutes. The researchers wanted to evaluate whether the new treatment had increased the value of μ in comparison to the previous treatment. The sample data yielded ?̅ = 2.17 and ? = 1.05: Using α = 05, what conclusions can you draw about the research hypothesis?