The following are prices of a sanitizer sold at a few selected stores in a District A during the COVID-19 pandemic. Based on the sample data, at 0.05 level of significance, can we conclude the average price of the sanitizer in District A is RM10.50? Make your conclusion using the p-value approach, with the aid of Mic. Office EXCEL.
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- Women are recommended to consume 1720 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1837, 1618, 1820, 1846, 1640, 1700, 1655, 1473, 1563, 1840, 1796, 1854 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = H1:H1: ? p μ Select an answer ≠ = < > The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean…Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x=98.34, y=100.45, r=0.940, P-value=0.000, and y=−3.86+1.06x, where x represents the IQ score of the twin born second. Find the best-predicted value of y given that the twin born second has an IQ of 103? Use a significance level of 0.05.Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.16, y = 102.3, r= 0.810, P-value = 0.000, and y = 23.09+0.78x, where x represents the IQ score of the wife. Find the best %3D %3D %3D predicted value of y given that the wife has an IQ of 109? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. .... The best predicted value of y is . (Round to two decimal places as needed.) Critical values of the pearson correlation coefficient r NOTE: To test Ho: p = 0 against H,: p#0, reject Ho |if the absolute value of r is greater than the critical value in the table. a = 0.05 a = 0.01 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40…
- Snow avalanches can be a real problem for travelers in the western United States and Canada. A very common type of avalanche is called the slab avalanche. These have been studied extensively by David McClung, a professor of civil engineering at the University of British Columbia. Suppose slab avalanches studied in a region of Canada had an average thickness of u = 67 cm. The ski patrol at Vail, Colorado, is studying slab avalanches in its region. A random sample of avalanches in spring gave the following thicknesses (in cm). 59 51 76 38 65 54 49 62 68 55 64 67 63 74 65 79 (i) Use a calculator with sample mean and standard deviation keys to find x and s. (Round your answers to two decimal places.) X= cm S= cm (ii) Assume the slab thickness has an approximately normal distribution. Use a 1% level of significance to test the claim that the mean slab thickness in the Vail region is different from that in the region of Canada. (a) What is the level of significance? State the null and…SHOW YOUR SOLUTION COMPLETELY. MAKE SURE YOUR FINALS ANSWERS SHOULD BE IN 4 DECIMAL PLACES.A small pilot study is conducted to investigate the effect of a nutritional supplement on total body weight. Six participants agree to take the nutritional supplement. To assess its effect on body weight, weights are measured before starting the supplementation and then after 6 weeks. The data are shown below. Is there a significant increase in body weight following supplementation? Run the test at a 5% level of significance. Demonstrate the five steps for hypothesis testing and explain your results. Subject Initial Weight Weight after 6 Weeks 1 155 157 2 142 145 3 176 180 4 180 175 5 210 209 6 125 126
- Samples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site. Pond 1: 37.03, 37.45, 36.75, 37.54, 37.71, 37.02, 37.32 Pond 2: 38.89, 39.05, 38.51, 38.53, 38.71 Use a 2% significance level to test the claim that the two ponds have the same mean salinity value. Assume that nothing is known about the population distribution of salinities. (a) Enter the rank values in the same order as in the original sample. The rank values for Pond 1 are: The rank values for Pond 2 are: (b) The test statistic is: . (c) The test critical value is: . (d) The conclusion isA. There is not sufficient evidence to indicate that the two ponds have different distributions of salinity values.B. There is sufficient evidence to indicate that the two ponds have different distributions of salinity values.In a random sample of males, it was found that 29 write with their left hands and 212 do not. In a random sample of females, it was found that 70 write with their left hands and 444 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below.a study of store checkout scanners, 1234 items were checked and 23 checked items were overcharges. Use a 0.05 significance level to test the claim that with scanners, 1% of sales are overchanrges. (Before scanners were used, the overcharge rate was estimated to be about 1%). a. Define the parameter A. mu = The proportion of all sales that are undercharges B. p = The proportion of all sales that are incorrect C. p = The proportion of all sales that are overcharges D. mu = The mean number of sales that are overcharges b. State the null and alternative hypotheses A. Upper H 0 : mu not equals 0.01 Upper H 1 : mu equals 0.01 B. Upper H 0 : p greater than 0.01 Upper H 1 : p equals 0.01 C. Upper H 0 : p equals 0.01 Upper H 1 : p not equals 0.01 D. Upper H 0 : p equals 23 Upper H 1 : p less than 23 c. Calculate the sample proportion ModifyingAbove p…
- A program administrator at a high school wanted to see if there was a significant association between experiencing verbal abuse and anxiety in teenage women. She wasn't sure what to expect. Perform the correct statistical procedure to assess the degree of association between these variables and interpret your findings. Set alpha = .05 for your statistical test. YOU CAN EITHER TYPE YOUR WORK OUT HERE OR TAKE A PICTURE OF HANDWRITTEN WORK AND EMAIL IT TO ME. %3D Anxiety Verbal Abuse 5. 4. 4.Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm Left arm 143 179 OA. Ho: H0 H₁: Hd=0 OC. Ho: P = 0 H₁: Hd 0 sufficient evidence to support the claim of a difference in measurements between the two arms.In a study performed on comfort food eating during times of stress, it was found that mean rated comfort food consumption level (on a scale from 1-20) for a group of students undertaking their exam period was 14. In comparison, a group of students who were not undertaking exams or examination preparation had a mean rated comfort food consumption level of 10. The pooled estimate of the population variance was 64. What is the estimated effect size (d) of the study? 0.80 0.06 0.50 2.00
