4) Recursive AnalysisHomework • UnansweredThe following algorithm takes an unsorted list of positive integers, along with two integers a and y. It returns the largest number,z, in the list such that either 2* = y or z9 = x is true. It returns 0 if no such z exists. The algorithm assumes that the listsize, n, is a power of 2 with n > 1.1 :integer xyMax(x, y, {a0,a1, ..., an-1})2 :if n == 13 :if (aðу) or(ažx)4return ao5 :else6 :return 07 :8 :# process the left half9 :10 :m1 = xyMax(x,y,{a0,..., a4 J-1})11 :12 :# process the right half13 :m2 = xyMax(x,y,{a ;,.., an-1})14 :15 :16 :# find the largest17 :18 :max %3D тi19 :if (m2 > max)20 :21 :22 :max %3D тgreturn max23 :end xyMaxWhat is the recurrence relation that counts the number of comparisons for this algorithm? (The critical steps are at lines 2, 3, and19.)What is a good big-O reference function for algorithm xyMax? (Hint: Which Master Theorem applies here?)

The following algorithm takes an unsorted list of positive integers, along with two integers I and y. It returns the largest number, z, in the list such that either z* = y or z = z is true. It returns 0 if no such z exists. The algorithm assumes that the list size, n, is a power of 2 with n >1. integer xyMax(x, y, {ao,a1, ..., an-1}) 1 : 2 : 3 : if n == 1 if (aj == y) or (až == x) =3= %3D3D 4 : return ao 5 : else 6 : return 0 7 8 : # process the left half 9 : m1 = xyMax(x,y,{a0,….., a]-1}) 10 : 11 : 12 : # process the right half 13 : 14 : m2 = xyMax(x,y,{a],..., an-1}) 15 : 16 : # find the largest 17 : 18 : max = mị 19 : if (m2 > max) 20 : max = m2 21 : 22 : return max 23 : end xyMax What is the recurrence relation that counts the number of comparisons for this algorithm? (The critical steps are at lines 2, 3, and 19.) What is a good big-O reference function for algorithm xyMax? (Hint: Which Master Theorem applies here?)

The following algorithm takes an unsorted list of positive integers, along with two integers I and y. It returns the largest number, z, in the list such that either z* = y or z = z is true. It returns 0 if no such z exists. The algorithm assumes that the list size, n, is a power of 2 with n >1. integer xyMax(x, y, {ao,a1, ..., an-1}) 1 : 2 : 3 : if n == 1 if (aj == y) or (až == x) =3= %3D3D 4 : return ao 5 : else 6 : return 0 7 8 : # process the left half 9 : m1 = xyMax(x,y,{a0,….., a]-1}) 10 : 11 : 12 : # process the right half 13 : 14 : m2 = xyMax(x,y,{a],..., an-1}) 15 : 16 : # find the largest 17 : 18 : max = mị 19 : if (m2 > max) 20 : max = m2 21 : 22 : return max 23 : end xyMax What is the recurrence relation that counts the number of comparisons for this algorithm? (The critical steps are at lines 2, 3, and 19.) What is a good big-O reference function for algorithm xyMax? (Hint: Which Master Theorem applies here?)

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Python’s list method sort includes the keyword argument reverse, whose defaultvalue is False. The programmer can override this value to sort a list in descendingorder. Modify the selectionSort function so that it allowsthe programmer to supply this additional argument to redirect the sort. selectionSort function: def selectionSort(lyst, profiler):i = 0 while i < len(lyst) - 1:minIndex = ij = i + 1 while j < len(lyst):profiler.comparison() # Countif lyst[j] < lyst[minIndex]:minIndex = jj += 1 if minIndex != i:swap(lyst, minIndex, i, profiler)i += 1 def swap(lyst, i, j, profiler):"""Exchanges the elements at positions i and j."""profiler.exchange() # Counttemp = lyst[i]lyst[i] = lyst[j]lyst[j] = temp Use this template in Python to modify the function above: def selection_sort(input_list, reverse):sorted_list = []#TODO: Your work here# Return sorted_listreturn sorted_listif __name__ == "__main__":my_list = [1, 2, 3, 4, 5]print(selection_sort(my_list, True)) # Correct Output: [5,…
ORIGINAL Q: Instead of reading in an entire list N1,N2,⋯N1,N2,⋯ all at once, some algorithms (depending on the task to be done) can read in only one element at a time and process that single element completely before inputting the next one. This can be a useful technique when the list is very big (e.g., billions of elements) and there might not be enough memory in the computer to store it in its entirety. Write an algorithm that reads in a sequence of values v≥0, one at a time, and computes the average of all the numbers. You should stop the computation when you input a value of V = −1. Do not include this negative value in your computations; it is not a piece of data but only a marker to identify the end of the list. PLEASE MODIFY THE FOLLOWING CODE SO THE USER INPUTS THE NUMBERS ONE BY ONE: ORIGINAL Q: Instead of reading in an entire list N1,N2,⋯N1 ,N2,⋯ all at once, some algorithms (depending on the task to be done) can read in only one element at a time and process that single…
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