The floor system of a residential building (LL=1.9KPa) consists of 125mm thick reinforced concrete slab (unit weight = 23.6 KN/m^3) resting on three 8 m spanned RC floor beams spaced at 2.5 meters on centers. Size of RC beam is 200mm x 450mm. NSCP 2015 Load factors: 1.2DL & 1.6LL. Assume simple supports. Calculate the ultimate/factored live load in KN/m. Express your answer in 1 decimal place.

Q: PROBLEM 1: The continuous floor beam ABCD is shown in the figure. It has a 100 mm slab thickness and…

A: Given, Slab thickness=100 mm Live load=3.6 kPa  L=8 m S=2.8 m Superimposed load =2.6 kPa Concrete…

Q: machine supporting structure consists of a hollow pipe of external diameter200 mm and wall thickness…

A:

Q: A timber beam is 100 mm wide and 150 mm deep. The beam is simply supported and carries a central…

A: Given- A timber beam- width=100 mm, depth=150 mm, Simply supported beam- central concentrated load=W…

Q: Q1) A cantilever reinforced concrete beam with rectangular section (as shown in Fig. 1) carries a…

A: P = 30KN W = 20KN/m For finding moment capacity in cracked section we have to remove steel and…

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.