The first thing we need to do is check to see if the distribution is approximately normal. np = 50(0.6) = 30 and ng = 50(0.4) 50(0.4) = 20 = Since np 10 and nq ≥ 10, we can conclude that p is approximately a normal distribution with • mean μ = 0.6 and p ● standard deviation бр = pq n = = 0.6(0.4) 50 pq n op nearest thousandth). = V (which is very close to what we saw in our simulation, standard error =0.063). = 0.24 50 Now find the approximation for samples of size 250. Is the standard deviation close to the standard error found in the simulation (standard error = 0.030)? - 0.0693 (Round to the Is the standard deviation close to the standard deviation (standard error) found

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Author:Amos Gilat
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The first thing we need to do is check to see if
the distribution is approximately normal.
50(0.6) = 30 and
ng = 50(0.4) = 20
np =
пр
Since np 10 and nq ≥ 10, we can
conclude that is approximately a normal
distribution with
• mean Up
• standard deviation
op
=
=
0.6 and
pq
n
=
=
0.6(0.4)
50
=
pq
n
0.24
50
(which is very close to what we saw in our
simulation, standard error =0.063).
standard error found in the simulation
(standard error = 0.030)?
ор
nearest thousandth).
Now find the approximation for samples of size
250. Is the standard deviation close to the
=
0.0693
(Round to the
Is the standard deviation close to the
standard deviation (standard error) found
in the simulation?
Transcribed Image Text:The first thing we need to do is check to see if the distribution is approximately normal. 50(0.6) = 30 and ng = 50(0.4) = 20 np = пр Since np 10 and nq ≥ 10, we can conclude that is approximately a normal distribution with • mean Up • standard deviation op = = 0.6 and pq n = = 0.6(0.4) 50 = pq n 0.24 50 (which is very close to what we saw in our simulation, standard error =0.063). standard error found in the simulation (standard error = 0.030)? ор nearest thousandth). Now find the approximation for samples of size 250. Is the standard deviation close to the = 0.0693 (Round to the Is the standard deviation close to the standard deviation (standard error) found in the simulation?
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