The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10 2 N₂05(9)→ 4 NO₂(g) + O₂(g) (a) How many moles of N₂O5 will remain after 3.0 min? 0.0146 mol (b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol? min (c) What is the half-life of N₂O5 at 70°C? min
The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10 2 N₂05(9)→ 4 NO₂(g) + O₂(g) (a) How many moles of N₂O5 will remain after 3.0 min? 0.0146 mol (b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol? min (c) What is the half-life of N₂O5 at 70°C? min
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 99QRT
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![The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10-3 s-1. Suppose we start with 0.0500 mol of N₂O5 (g) in a volume of 4.5 L.
2 N₂O5(9)→ 4 NO₂(g) + O₂(g)
(a) How many moles of N₂O5 will remain after 3.0 min?
0.0146
mol
(b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol?
min
(c) What is the half-life of N₂O5 at 70°C?
min](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b544e27-b206-4737-bcd7-19b8530d4e02%2Fb72facd1-6cd7-41fd-afc8-72edc65385f9%2F3le9s2o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The first-order rate constant for the decomposition of N₂O5, given below, at 70°C is 6.82 x 10-3 s-1. Suppose we start with 0.0500 mol of N₂O5 (g) in a volume of 4.5 L.
2 N₂O5(9)→ 4 NO₂(g) + O₂(g)
(a) How many moles of N₂O5 will remain after 3.0 min?
0.0146
mol
(b) How many minutes will it take for the quantity of N₂O5 to drop to 0.005 mol?
min
(c) What is the half-life of N₂O5 at 70°C?
min
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