The first iteration of the Newton-Raphson method to solve the system of equations f(x,y)=x2+y2−2=0f(x,y)=x2+y2−2=0 and g(x,y)=2y−2x2=0g(x,y)=2y−2x2=0 The initial approximation is x0=y0=0.7071x0=y0=0.7071 Select one: a. x1=0.69289x1=0.69289 y1=0.61032y1=0.61032 b. x1=1.08579x1=1.08579 y1=1.03554y1=1.03554 c. x1=1.57429x1=1.57429 y1=1.06232y1=1.06232 d. x1=1.77298x1=1.77298 y1=0.64332
The first iteration of the Newton-Raphson method to solve the system of equations f(x,y)=x2+y2−2=0f(x,y)=x2+y2−2=0 and g(x,y)=2y−2x2=0g(x,y)=2y−2x2=0 The initial approximation is x0=y0=0.7071x0=y0=0.7071 Select one: a. x1=0.69289x1=0.69289 y1=0.61032y1=0.61032 b. x1=1.08579x1=1.08579 y1=1.03554y1=1.03554 c. x1=1.57429x1=1.57429 y1=1.06232y1=1.06232 d. x1=1.77298x1=1.77298 y1=0.64332
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The first iteration of the Newton-Raphson method to solve the system of equations
f(x,y)=x2+y2−2=0f(x,y)=x2+y2−2=0 and
g(x,y)=2y−2x2=0g(x,y)=2y−2x2=0
The initial approximation is x0=y0=0.7071x0=y0=0.7071
Select one:
a. x1=0.69289x1=0.69289
y1=0.61032y1=0.61032
y1=0.61032y1=0.61032
b. x1=1.08579x1=1.08579
y1=1.03554y1=1.03554
y1=1.03554y1=1.03554
c. x1=1.57429x1=1.57429
y1=1.06232y1=1.06232
y1=1.06232y1=1.06232
d. x1=1.77298x1=1.77298
y1=0.64332
y1=0.64332
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