The first four moments of a distribution about the value '4' are - 1-5, 17, – 30 and 108, find the moments about mean and origin.
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- The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EUA soft drink vending machine is set to serve an average of 259 milliliters per glass. If the amount of drink is normally distributed with a standard deviation equal to 18 milliliters, how many glasses on average will be spilled if 277 milliliter glasses are used for the next 1080 drinks?Today, the waves are crashing onto the beach every 5 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 2 seconds after the person arrives is P(x = 2) = The probability that the wave will crash onto the beach between 0.4 and 2.9 seconds after the person arrives is P(0.4 < x < 2.9) = The probability that it will take longer than 1.5 seconds for the wave to crash onto the beach after the person arrives is P(x > 1.5) = Suppose that the person has already been standing at the shoreline for 1.3 seconds without a wave crashing in. Find the probability that it will take between 2.7 and 4.8 seconds for the wave to crash onto the shoreline. 27% of the time a person will wait at least how long before the wave crashes in?…
- Today, the waves are crashing onto the beach every 6 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 6 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 3.9 seconds after the person arrives is P(x = 3.9) =For the residents in 2014, use R to calculate the interval with 99% certainty that the interval contains the actual population mean of the residents by census tracts. Type in the interval with keyboard. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years. POP2014: 3072, 1989, 3794, 2689, 3211, 3722, 4385, 4009, 7598, 3862, 3097, 2726, 4881, 4157, 2570, 2512, 2518, 4863, 4147, 7139, 6067, 6819, 3705, 3239, 3824, 4977, 2576, 2940, 9791, 5231, 5634, 5337, 4205, 3888, 5562, 3335, 3770, 1808, 2045, 1532, 5420, 4993, 6109, 4377, 5424, 4976, 4507, 3738, 2827, 3485, 1559, 5199, 4702, 3971, 3803, 3356, 4670, 3816, 5477, 4760, 3126, 3630, 3755, 3795, 2578, 3382, 4005, 2442, 6096, 3799, 3843, 3836, 6046, 6431, 3561, 3142, 4829, 5058, 2471, 6119, 3523, 3094, 3146, 3356, 2618, 2366, 4266, 4016, 6080, 1554, 6878, 3645,…a random sample of 25 children is selected and each is given several pieces of yummy gummy candy. twenty two of the children indicated they like the candy. find the point of estimate as a decimal for the true proportion of children that like
- What value should go in the overlap of the two circles? (that's where the 'X' is). Explain your reasoningThe chart to the right shows that a professor's grading distribution is bell shaped, or normally shaped. The mean of the distribution is 74 and the standard deviation is 9. Using a Continuous Variable Normal Bell Distribution Model, calculate the minimum test score needed to score in the top 5% of the class. Complete your work in the worksheet by listing the formula inputs, labels for the formula inputs and make your calculations with formulas. This test problem is similar to what you studied in video # 32, 33 and 34 and homework problems # 17, 21 and 23. Relative Frequency Frequency Professor looks at all test score for a particular test (this is population data), and observes: 0.5 0.45 0.4 0.35 0.3 0.25 0.2 0.15 0.1 0.05 0 Mean = 74 Median = 74 Mode = 73 SD=9 0 0 0 up to 10 up 10 to 20 0 20 up to 30 0 30 up to 40 2 40 up to 50 29 50 up to 60 X = Score 112 60 up to 70 225 70 up to 80 111 80 up to 90 21 2 90 up 100 up to 100 to 110Suppose X ~ N(6, 2). What value of x is two standard deviations to the right of the mean?
- The actual value of the standard deviation can be zero or a positive number, why value can never be a negative number?A distribution with u=55 and o=6 is being standardized so that the new mean and standard deviation will be u =50 and o=10.When the distribution is standardized,which value will be obtained for a score of x=58 from the original distribution? x=53 x=55 X=58 x=61for data set of the pulse rates for a sample of adult females the lowest pulse rate is 36 bpm the mean of the list of pulse rate is X bar equals 72 bpm and their standard deviation is 12.9 bpm. what is the difference between the pulse rate of 36 bpm and the meatballs rid of the females how many celebrations is that the difference found in part a convert the pulse rate of 36 bpm to a z score if we consider pulse rates that convert to a Z score between -2 and 2 to be neither significantly lower significantly high is the pulse rate of 36bpm significant
