The figure shows vertical parallel plates of length L=5 cm separated by 4 cm. Electrons (mass me = 9.11x10-31 kg) enter vertically at a speed v0 = 1x106 m/s. %3D The potential difference between the plates is initially set to VA-VB = +1OV. At this potential difference the electrons impact one of the plates. (a) Which plate (A/B) is hit by the electrons?Ealculate the speed of the electrons as they impact the corresponding plate.

University Physics Volume 2
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Chapter7: Electric Potential
Section: Chapter Questions
Problem 37P: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104...
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The figure shows vertical parallel plates of length L= 5 cm separated by 4 cm.
Electrons (mass me = 9.11x10-31 kg) enter vertically at a speed v0 = 1x106 m/s.
The potential difference between the plates is initially set to VA-VB = +10V. At this
potential difference the electrons impact one of the plates.
(a) Which plate (A/B) is hit by the electrons?-
ifalculate the speed of the
electrons as they impact the corresponding plate.
Transcribed Image Text:The figure shows vertical parallel plates of length L= 5 cm separated by 4 cm. Electrons (mass me = 9.11x10-31 kg) enter vertically at a speed v0 = 1x106 m/s. The potential difference between the plates is initially set to VA-VB = +10V. At this potential difference the electrons impact one of the plates. (a) Which plate (A/B) is hit by the electrons?- ifalculate the speed of the electrons as they impact the corresponding plate.
ING 2021
Transcribed Image Text:ING 2021
Expert Solution
Step 1

Given :

Length of the parallel plates L=5 cm

distance between plates d=4 cm=0.04 m

distance from plate A s=1 cm=0.01 m

Potential difference between plates VA-VB=+10 V

Initial speed of the electron v0=1*106 m/s

mass of the electron me=9.11*10-31 Kg

charge on electron qe=1.6*10-19 C

 

Determine:

Speed of the electron when it hits the plate.

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