The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at 6, = 25.0°. Force F, has a magnitude of 7.00 N and is at 82 = 26.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0i – 12.0j) m/s, and (c) has the V = (14.0î – 14.0fj) m/s?, where t is time?

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Chapter1: Units, Trigonometry. And Vectors
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The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at e, = 25.0°. Force F2
has a magnitude of 7.00 N and is at 02 = 26.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0i – 12.0j) m/s, and (c) has the
V = (14.0tî – 14.0fj) m/s², where t is time?
Transcribed Image Text:The figure shows an overhead view of a 0.0260 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F, has a magnitude of 6.00 N and is at e, = 25.0°. Force F2 has a magnitude of 7.00 N and is at 02 = 26.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0i – 12.0j) m/s, and (c) has the V = (14.0tî – 14.0fj) m/s², where t is time?
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