An applied force of 42.3 N directed at an angle of -17.7 degrees with respect to the +x direction acts on a 2.95 kg mass that is initially at rest while on a horizontal surface. In moving a distance of 2.67 m in the +x direction, the object changes its kinetic energy by 31.5 J. What is the coefficient of kinetic friction
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An applied force of 42.3 N directed at an angle of -17.7 degrees with respect to the +x direction acts on a 2.95 kg mass that is initially at rest while on a horizontal surface. In moving a distance of 2.67 m in the +x direction, the object changes its kinetic energy by 31.5 J. What is the coefficient of kinetic friction
Given:
- The force applied F = 42.3 N.
- The inclination of the incline θ = -17.7o.
- The mass of the body m = 2.95 kg.
- the distance travelled by the body s = 2.67 m.
- The change in kinetic energy ∆K = 31.5 J.
f -- frictional force =
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