The figure shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley and pulls with a force of magnitude 94.9 N on the wall to which it is attached. The tensions in the shorter cords are T = 68.7 N, T2 = 46.9 N, and T3 = 5.51 N. What are the masses of (a) disk A, (b) disk B, (c) disk C, and (d) disk D? B T2 T3 D
The figure shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley and pulls with a force of magnitude 94.9 N on the wall to which it is attached. The tensions in the shorter cords are T = 68.7 N, T2 = 46.9 N, and T3 = 5.51 N. What are the masses of (a) disk A, (b) disk B, (c) disk C, and (d) disk D? B T2 T3 D
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Transcribed Image Text:The figure shows an arrangement in which four disks are suspended by cords. The longer, top cord loops over a frictionless pulley and
pulls with a force of magnitude 94.9 N on the wall to which it is attached. The tensions in the shorter cords are T1 = 68.7 N, T2 = 46.9N,
and T3 = 5.51 N. What are the masses of (a) disk A, (b) disk B, (c) disk C, and (d) disk D?
(a) Number
Units
(b) Number
Units
(c) Number
Units
(d) Number
Units
>
Expert Solution
Step 1
Given data
To calculate the masses of the four discs we have to apply the conditions of equilibrium along vertical direction. According to this the force acting in down ward direction is equal to the total force acting in the upward direction under the equilibrium of the body. The main forces in this problem are due to weight and tension in the discs.
The weight of the body can be given by
Here, m is the mass of the body.
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