The figure shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P5.20b) y = Determine the point of maximum deflection (that is, the value of x where dy/dx=0). Then substitute this value into Eq. (P5.20) to determine the value of the maximum deflection. Use the following parameter values in your computation: L= 600 cm, E= 50,000 kN/cm?, I= 30,000 cm4, and w0=2.5 KN/cm. w0 (-x5+2L?x3 – L*x). 120EIL (a) (x - Ly- 0) (x= 0. y = 0) (b)
The figure shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P5.20b) y = Determine the point of maximum deflection (that is, the value of x where dy/dx=0). Then substitute this value into Eq. (P5.20) to determine the value of the maximum deflection. Use the following parameter values in your computation: L= 600 cm, E= 50,000 kN/cm?, I= 30,000 cm4, and w0=2.5 KN/cm. w0 (-x5+2L?x3 – L*x). 120EIL (a) (x - Ly- 0) (x= 0. y = 0) (b)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![The figure shows a uniform beam
subject to a linearly increasing
distributed load. The equation for the
resulting elastic curve is (see Fig.
P5.20b) y = 20FL (-x + 2L?x3 – L*x).
Determine the point of maximum
deflection (that is, the value of x
where dy/dx=0). Then substitute this
value into Eq. (P5.20) to determine the
value of the maximum deflection. Use
the following parameter values in your
computation: L= 600 cm, E= 50,000
kN/cm?, I= 30,000 cm4, and wO=2.5
KN/cm.
Wo
w0
L.
(a)
(x - Ly - 0)
(x= 0, y = 0)
(b)
ww](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa9e1313-b26d-4c14-b120-a6974fef4a74%2F5644b1cf-8ea4-4e21-94ed-0d8a180abfaf%2F5addpfd.bmp&w=3840&q=75)
Transcribed Image Text:The figure shows a uniform beam
subject to a linearly increasing
distributed load. The equation for the
resulting elastic curve is (see Fig.
P5.20b) y = 20FL (-x + 2L?x3 – L*x).
Determine the point of maximum
deflection (that is, the value of x
where dy/dx=0). Then substitute this
value into Eq. (P5.20) to determine the
value of the maximum deflection. Use
the following parameter values in your
computation: L= 600 cm, E= 50,000
kN/cm?, I= 30,000 cm4, and wO=2.5
KN/cm.
Wo
w0
L.
(a)
(x - Ly - 0)
(x= 0, y = 0)
(b)
ww
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