The figure shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P5.20b) y = Determine the point of maximum deflection (that is, the value of x where dy/dx=0). Then substitute this value into Eq. (P5.20) to determine the value of the maximum deflection. Use the following parameter values in your computation: L= 600 cm, E= 50,000 kN/cm?, I= 30,000 cm4, and w0=2.5 KN/cm. w0 (-x5+2L?x3 – L*x). 120EIL (a) (x - Ly- 0) (x= 0. y = 0) (b)

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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The figure shows a uniform beam
subject to a linearly increasing
distributed load. The equation for the
resulting elastic curve is (see Fig.
P5.20b) y = 20FL (-x + 2L?x3 – L*x).
Determine the point of maximum
deflection (that is, the value of x
where dy/dx=0). Then substitute this
value into Eq. (P5.20) to determine the
value of the maximum deflection. Use
the following parameter values in your
computation: L= 600 cm, E= 50,000
kN/cm?, I= 30,000 cm4, and wO=2.5
KN/cm.
Wo
w0
L.
(a)
(x - Ly - 0)
(x= 0, y = 0)
(b)
ww
Transcribed Image Text:The figure shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P5.20b) y = 20FL (-x + 2L?x3 – L*x). Determine the point of maximum deflection (that is, the value of x where dy/dx=0). Then substitute this value into Eq. (P5.20) to determine the value of the maximum deflection. Use the following parameter values in your computation: L= 600 cm, E= 50,000 kN/cm?, I= 30,000 cm4, and wO=2.5 KN/cm. Wo w0 L. (a) (x - Ly - 0) (x= 0, y = 0) (b) ww
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