The figure shows a person's foot. In that figure, the Achilles tendon exerts a force of magnitude F = 720 N. What is the magnitude of the torque that this force produces about the ankle joint? The image is a diagram illustrating the biomechanics of the foot, specifically focusing on the ankle joint. The diagram shows a side view of the foot and ankle, with markings to indicate angle measurements and distances relevant to movement dynamics.Key Features:1. **Angle of Flexion**: The foot is flexed at an angle of 50 degrees, which is likely meant to demonstrate dorsiflexion or plantarflexion in the context of the ankle joint.2. **Force (F)**: An arrow labeled "F" indicates the direction of force applied at or near the toes, pointing upwards and slightly forward.3. **Distance Measurement**: A horizontal distance from the rear of the heel to the point of force application measures 3.5 cm. This is significant in understanding leverage and the distribution of force across the foot.4. **Ankle Joint**: The joint is highlighted to show its role as the pivotal point for foot movement.This diagram could be used to explain the mechanics of muscles, tendons, and forces that act upon the ankle joint during movement, relevant to studies in biomechanics, physical therapy, and sports science.

Torque is defined as moment of force . It is product of force and perpendicular distance from axis of rotation . τ=F.lAs l=dcosθ⇒τ=Fdcosθ Given : F = 720 N d=3.5 cm =3.5×10-2 mθ=50°Plugging given values of F and d in formula we get τ=720×3.5×10-2Cos50 =2520×10-2×0.642 =16.2 N.m Answer: Magnitude of torque is 16.2 N.m .