The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's law gives RI += E(t). But I = dQ/dt (see this example), so we have R do dt 름이 E(t). Suppose the resistance is 22, the capacitance is 0.01 F, the electromotive force is E(t) = 50 sin(60t) V, and the initial charge is Q = 0 C. Find the charge Q (in C) at time t. Q(t)= C Find the current I (in A) at time t. I(t) = A

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Chapter1: Chemical Foundations
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The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C,
where Q is the charge (in coulombs), so in this case Kirchhoff's law gives
RI += E(t).
But I = dQ/dt (see this example), so we have
R do
dt
름이
E(t).
Suppose the resistance is 22, the capacitance is 0.01 F, the electromotive force is E(t) = 50 sin(60t) V, and the initial charge is Q = 0 C.
Find the charge Q (in C) at time t.
Q(t)=
C
Find the current I (in A) at time t.
I(t) =
A
Transcribed Image Text:The figure shows a circuit containing an electromotive force, a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (2). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's law gives RI += E(t). But I = dQ/dt (see this example), so we have R do dt 름이 E(t). Suppose the resistance is 22, the capacitance is 0.01 F, the electromotive force is E(t) = 50 sin(60t) V, and the initial charge is Q = 0 C. Find the charge Q (in C) at time t. Q(t)= C Find the current I (in A) at time t. I(t) = A
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