The Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are and , respectively. The resistance coefficents for two bearings are and . The cross section areas of two branch pipes are . The engergy loss caused by friction can be ignored. The engergy loss cuased by one bend is .
The Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are and , respectively. The resistance coefficents for two bearings are and . The cross section areas of two branch pipes are . The engergy loss caused by friction can be ignored. The engergy loss cuased by one bend is .
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The Figure shown below is a parallel pipeline system with two branches used to supply lubricating water to the bearings. The main line and two branches use the same size of pipes. The pressures at section 1 and section 2 are and , respectively. The resistance coefficents for two bearings are and . The cross section areas of two branch pipes are . The engergy loss caused by friction can be ignored. The engergy loss cuased by one bend is .
(1) Select the simplified general energy equations for section 1 and 2_________
A. B. C. D.

Transcribed Image Text:The Figure shown below is a parallel pipeline system with two branches used to supply
lubricating water to the bearings. The main line and two branches use the same size of pipes.
The pressures at section 1 and section 2 are p₁=398.1kPa and p₂=300kPa,
2
1
respectively. The resistance coefficents for two bearings are K₁=5 and K₂=12. The cross
= 1.5x 10-4m². The engergy loss caused
section areas of two branch pipes are A_=A₁ =
by friction can be ignored. The engergy loss cuased by one bend is h₂ = 0.2 m.
(1) Select the simplified general energy equations for section 1 and 2
K₁
OA
h₁
7
P₁-P₂
2
7
P₁
h. =
+
P2
1
49.43
=
L
1
2g
Y
K₂
2g
P₂
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