The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage, with L1- 4 ft, L2- 0.5 ft, and L3 - 1.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in Ib/ft. Let g - 32.2 ft/s?. %3D Pressure gage Air Oil (p = 55 Ibv/t) Pam Mercury ( p = 845 Ib/f') 8 = 322 fis? Determine the reading of the pressure gage, in Ibf/in.? (gage).

icon
Related questions
Question
100%
The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage,
with L1 = 4 ft, L2 = 0.5 ft, and L3 = 1.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in Ib/ft°. Let g = 32.2
ft/s?.
Pressure
gage
Air
Oil (p = 55 Ib/ft)
Patm
Mercury (p = 845 Ib/ft')
8 = 32.2 fils?
Determine the reading of the pressure gage, in Ibf/in.? (gage).
Transcribed Image Text:The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage, with L1 = 4 ft, L2 = 0.5 ft, and L3 = 1.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in Ib/ft°. Let g = 32.2 ft/s?. Pressure gage Air Oil (p = 55 Ib/ft) Patm Mercury (p = 845 Ib/ft') 8 = 32.2 fils? Determine the reading of the pressure gage, in Ibf/in.? (gage).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer