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The figure below shows an outstretched arm (0.61 m in length) that is parallel to the floor. The arm is pulling downward against the ring attached to the pulley system, in order to hold the 98 N weight stationary. To pull the arm downward, the latissimus dorsi muscle applies the force M in the figure, at a point that is 0.069 m from the should joint and oriented at an angle of 29°. The arm has a weight of 47 N and a center of gravity (cg) that is located 0.28 m from the shoulder joint. 0.61 m 0.28 m 0.069 m Axis at 98 N shoulder joint cg 29 M

The figure below shows an outstretched arm (0.61 m in length) that is parallel to the floor. The arm is pulling downward against the ring attached to the pulley system, in order to hold the 98 N weight stationary. To pull the arm downward, the latissimus dorsi muscle applies the force M in the figure, at a point that is 0.069 m from the should joint and oriented at an angle of 29°. The arm has a weight of 47 N and a center of gravity (cg) that is located 0.28 m from the shoulder joint. 0.61 m 0.28 m 0.069 m Axis at 98 N shoulder joint cg 29 M

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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outstretched arm (2) part 1

 

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The figure below shows an outstretched arm (0.61 m in length) that is parallel to the floor. The arm is pulling downward against the ring attached to the pulley system, in order to hold the 98 N weight stationary. To pull the arm downward, the latissimus dorsi muscle applies the force M in the figure, at a point that is 0.069 m from the should joint and oriented at an angle of 29°. The arm has a weight of 47 N and a center of gravity (cg) that is located 0.28 m from the shoulder joint. 0.61 m 0.28 m 0.069 m Axis at 98 N shoulder joint cg 29 M Aldentify all the forces on the arm and draw an accurate and complete free body diagram on both the arm and the 98 N weight. You may draw on the figure if you wish. B Write down the correct equation of motion ON THE 98 N WEIGHT by summing all the forces acting on it using Newton's 2nd Law of Motion. You must identify and draw your chosen coordinate system. ( Write down the correct equation of motion ON THE ARM by summing all the forces acting on it using Newton's 2nd Law of Motion. You must identify and draw your chosen positive direction for the torque. (Note: The direction of the torque is not the same as the direction of rotation. Watch the relevant exercise videos again if you're not sure, and carefully listen to what I am saying about the direction of rotation and the direction of the torque.) D How are the force due to the string on the hand related to the force by string on the block related? Which law of Newton describes this relationship? E Solve for the magnitude of M. FInterpret this result. In other words, is this a significant amount of force for a single set of muscles just to be able to hold the weight down?
Transcribed Image Text:The figure below shows an outstretched arm (0.61 m in length) that is parallel to the floor. The arm is pulling downward against the ring attached to the pulley system, in order to hold the 98 N weight stationary. To pull the arm downward, the latissimus dorsi muscle applies the force M in the figure, at a point that is 0.069 m from the should joint and oriented at an angle of 29°. The arm has a weight of 47 N and a center of gravity (cg) that is located 0.28 m from the shoulder joint. 0.61 m 0.28 m 0.069 m Axis at 98 N shoulder joint cg 29 M Aldentify all the forces on the arm and draw an accurate and complete free body diagram on both the arm and the 98 N weight. You may draw on the figure if you wish. B Write down the correct equation of motion ON THE 98 N WEIGHT by summing all the forces acting on it using Newton's 2nd Law of Motion. You must identify and draw your chosen coordinate system. ( Write down the correct equation of motion ON THE ARM by summing all the forces acting on it using Newton's 2nd Law of Motion. You must identify and draw your chosen positive direction for the torque. (Note: The direction of the torque is not the same as the direction of rotation. Watch the relevant exercise videos again if you're not sure, and carefully listen to what I am saying about the direction of rotation and the direction of the torque.) D How are the force due to the string on the hand related to the force by string on the block related? Which law of Newton describes this relationship? E Solve for the magnitude of M. FInterpret this result. In other words, is this a significant amount of force for a single set of muscles just to be able to hold the weight down?
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