The figure below shows a vertical projectile. If the projectile's initial velocity (v1) is 200 m/s and the launch angle θ = 66°, determine the maximum horizontal displacement (Δxmax) or range (R).
Q: A batter hits the baseball A with an initial velocity of vo = 93 ft/sec directly toward fielder B at…
A:
Q: Consider a projectile being launched with an initial speed of 49.5 m/s at a variety of initial…
A: a) Given data The initial velocity of the projectile launched is given as u = 49.5 m/s. The angle…
Q: 1. A projectile is launched from ground level at an angle of 150 above the horizontal. It returns to…
A:
Q: Now let's consider a projectile problem in which the initial velocity is specified in terms of a…
A:
Q: A batter hits the baseball A with an initial velocity of vo = 94 ft/sec directly toward fielder B at…
A:
Q: the shot put, a heavy lead weight—the "shot"—is given an initial velocity, starting from an initial…
A:
Q: A projectile is launched in such a way that its maximum height is one-half its total range. At what…
A: Expression for maximum height of the projectile - hmax=vi2sin2θ2g Expression for total range of the…
Q: A projectile is launched with an initial velocity of 100 m/s at a 30° angle above the horizontal.…
A:
Q: Consider a projectile being launched with an initial speed of 58 m/s at a variety of initial angles.…
A:
Q: man was standing on one side of the roof of a building 145 meters above the ground and shot a…
A: Given: The initial velocity of the object is 53 m/s. The angle of the projection is 30o. The initial…
Q: A projectile is shot in the air from ground level with an initial velocity of 500 m/sec at an angle…
A: Initial velocity (u) = 500 m/s Launching angle (θ) = 45o
Q: A projectile is landing with an angle of 60 degrees below the horizontal. It is thrown horizontally…
A:
Q: Solve the problem. Unless stated otherwise, assume that the projectile flight is ideal, that the…
A:
Q: projectile is fired with an initial speed of 37.6 m/s at an angle of 42.9 above the horizontal on a…
A: given: initial speed vo=37.6 m/s angle θ = 42.9o
Q: What is the initial speed of the projectile?
A:
Q: A batter hits the baseball A with an initial velocity of vo = 91 ft/sec directly toward fielder B at…
A: This is a question based on projectile motion, initial height of the ball, h=2.4ft initial velocity…
Q: The highest barrier that a projectile can clear is 18.7 m, when the projectile is launched at an…
A: Maximum height of projectile motion is, hmax=u2sin2θ2g Here, u is initial velocity and θ is angle…
Q: In the absence of air resistance, a projectile is launched from and returns to ground level. It has…
A: Given value--- In the absence of air resistance, a projectile is launched from and returns to…
Q: (1) How much does the arrow clear the treetop if 6 = 30.0°? (A) 3.6 m; (B) 3.1 m; (C) 2.6 m; (D) 2.1…
A: Projectile A projectile is an object that is thrown without any fuel. The object is generally thrown…
Q: A guy is standing on a relatively flat surface (h = 0 m). A pesky drone is flying overhead at a…
A: Let us assume the arrow hits the drone when it has reached its maximum height. Let v1 be the…
The figure below shows a vertical projectile. If the projectile's initial velocity (v1) is 200 m/s and the launch angle θ = 66°, determine the maximum horizontal displacement (Δxmax) or range (R).
Trending now
This is a popular solution!
Learn your way
Includes step-by-step video
Step by step
Solved in 2 steps
- If the stone had been thrown front the cliff too with the same initial speed and the same angle, but above the horizontal, would it’s impact velocity be different?A projectile is shot in the air from ground level with an initial velocity of 490 m/sec at an angle of 60° with the horizontal. (a)At what time (in seconds) is the maximum range of the projectile attained? (b)What is the maximum range (in meters)?Consider a projectile being launched with an initial speed of 43 m/s at a variety of initial angles. Refer to the figure. What is the range, in meters, of the projectile if it is launched at an angle of θ1 = 79.7°? What is the range, in meters, of the projectile if it is launched at an angle of θ2 = 40.5°? What is the range, in meters, of the projectile if it is launched at an angle of θ3 = 90 − 79.7°, the complement of θ1?
- (a) From a balcony a child fires a toy arrow down to the ground below. The arrow has initial speed 12 m/s and is aimed at an angle of 30° below the horizontal. The arrow takes 1.2 seconds to hit the ground. (i) Calculate the initial horizontal (✰) and vertical (ŷ) velocity components of the arrow. (ii) Calculate the height of the balcony. (b) A projectile is launched with an initial speed of 75 m/s at an angle of 52° above the horizontal. If it lands at the same height from which it was launched, calculate how long the projectile remains in the air.Consider a projectile launched at a height h feet above the ground and at an angle ? with the horizontal. If the initial velocity is v0 feet per second, the path of the projectile is modeled by the parametric equations x = t(v0 cos(?)) and y = h + (v0 sin ?)t - 16t2.Let h=6, v0=63.25, and ?=0.79. What is the range of the projectile (i.e., how far does it travel? Round your answers to two decimal places).Use a graphing utility to obtain the path of a projectile launched from the ground (h = 0) at the specified values of θ = 35°, v0 = 300 feet per second. In the exercise, use the graph to determine the maximum height and the time at which the projectile reaches its maximum height. Also use the graph to determine the range of the projectile and the time it hits the ground. Round all answers to the nearest tenth.
- The initial speed of a tennis ball is 57.5 m/s and the launch angle is ?i = 16°. Neglect air resistance.Question 1) What is the maximum height, h, of the tennis ball? in mQuestione 2) What is the range, R, of the tennis ball? in m info given: what angle results in the greatest height=90 For this 90° angle, the horizontal component of velocity is zero, so the initial velocity is completely in the vertical direction, resulting in greatest height Kato tries substituting ty,max for t, 0 for yi, and h for yf, and gets h = vi2 sin2 ?i 2g When ?i = 90°, sin2 ?i is maximum, so h is maximum what angle results in the maximum horizontal range=45° I substituted 2vi sin ?i g into the expression for the horizontal component of velocity, (vi cos ?i)t, and got R = 2vi2 sin ?i cos ?i g when ?i = 45°, 2?i = 90°, and sin 90° = 1, which is its maximum value.This problem will involve deriving a formula or two for a projectile launched from one height and angle and landing at a different height on Earth. Begin with a projectile launched at angle 0 above horizontal from a height y₁ with initial velocity Vo. The projectile lands at a point with height y₂. These are the given quantities: vo, 0, y₁, y2 and g. Construct formulae for each of the following, as. a function of given quantities the horizontal distance traveled. the maximum height reached. the time taken. the angle of impact. (find the final velocity components first).A stone is flying with initial velocity Vo= 40 m/s and 45° from x-axis. It lands on a roof of a building 25 m above the horizon. Find total time of the flight, maximum height(position) of the stone and maximum horizontal displacement.
- In 2007, Michael Carter (U.S.) set a world record in the shot put with a throw of 24.77 m. What was the initial speed of the shot if he released it at a height of 2.10 m and threw it at an angle of 38.0° above the horizontal? (Although the maximum distance for a projectile on level ground is achieved at 45° when air resistance is neglected, the actual angle to achieve maximum range is smaller; thus, 38° will give a longer range than 45° in the shot put.)a) Where is the shot-put when t=2?