### Description of the ScenarioThe figure depicts a titanium ball with a mass of 3.56 kg bouncing off a wall. The ball is shown at three points during this process: before, during, and after the impact. The ball has the same speed of 10.0 m/s just before and just after the impact. The angle the ball's path makes with the wall is 60.0°. **Assumptions:**- The effect of gravity on the ball is negligible during the short time of impact.- The contact time with the wall is given as 0.190 s. ### Problem StatementCalculate the average force (in Newtons) exerted by the wall on the ball during the impact. ### Components of the Image1. **Diagram:** - The diagram shows the path of the ball approaching and then leaving the wall. - It includes vectors representing velocity before and after impact. - There is a vertical wall indicated with a line, with the rebound path forming symmetrical angles with the normal to the wall.2. **Vector Representation:** - The velocity vectors are illustrated with red arrows. - θ is indicated as 60° for both the incoming and outgoing paths concerning the wall normal.### Calculation of ForceTo find the average force, the change in momentum and contact time must be considered:1. **Change in Velocity:** - Compute the change in momentum by calculating the components of velocity perpendicular to the wall before and after the collision. - The horizontal component of the velocity will change direction, thus contributing to the momentum change.2. **Momentum Change and Force Calculation:** - Use the impulse, which is change in momentum, and the formula \( F = \frac{\Delta p}{\Delta t} \) - Calculate the average force exerted using the provided magnitude and contact duration.Given that the velocity does not change in magnitude but only in direction, only the components perpendicular to the wall need consideration for the momentum calculation. By symmetry and the provided vectors, the momentum change is calculated based on the absolute differences in these components.### Interactive ComponentA box is shown for entering:- **Magnitude**: calculated to be 171.28 N - **Direction**: indicated as in the negative x-direction.

Answered: Image /qna-images/answer/8f0f47c8-3f8c-41d2-a973-2088e6aec908.jpg

The figure below shows a titanium bail with a mass of 3.56 kg bouncing off a wall. The bal has the same speed just before and just afer the impact (v- 10.0 mys), and the angle Rs path makes with the wall is e 60.0 as shown. (Because we are analyzing the motion of the ball over a very short time just before and after impact, you may safely ignore the effect of gravity on the ball.) The ball is in contact with the wall for 0.180 s. What is the averape force (in N) exerted by the wall on the ball during the impact magnitude 171.20 direction direction

The figure below shows a titanium bail with a mass of 3.56 kg bouncing off a wall. The bal has the same speed just before and just afer the impact (v- 10.0 mys), and the angle Rs path makes with the wall is e 60.0 as shown. (Because we are analyzing the motion of the ball over a very short time just before and after impact, you may safely ignore the effect of gravity on the ball.) The ball is in contact with the wall for 0.180 s. What is the averape force (in N) exerted by the wall on the ball during the impact magnitude 171.20 direction direction

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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