The figure below shows a cross sectional view of 5 wires separated by a distance d = 0.0150 m. The currents in the wires are into the page for wires 1, 3, and 5 and out of the page for wires 2 and 4. The amount of current through each of the wires is as follows: ₁ - 309 A, 12 = 340 A, 13 = 353 A, 14 = 223 A, and is = 312 A. What is the magnitude of the force per unit length on wire 1 due to the other wires? i N/m Z 2 d→→ ←d. 3 d 4 d 5 O-Y y

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Chapter1: Units, Trigonometry. And Vectors
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The figure below shows a cross sectional view of 5 wires separated by a distance d = 0.0150 m. The currents in the wires are into the
page for wires 1, 3, and 5 and out of the page for wires 2 and 4. The amount of current through each of the wires is as follows: 1₁ = 309
A, 12 = 340 A, 13 = 353 A, 14 = 223 A, and is = 312 A. What is the magnitude of the force per unit length on wire 1 due to the other wires?
i
N/m
Z
2
d→→ ←d
3
d
4
d
5
O-Y
y
Transcribed Image Text:The figure below shows a cross sectional view of 5 wires separated by a distance d = 0.0150 m. The currents in the wires are into the page for wires 1, 3, and 5 and out of the page for wires 2 and 4. The amount of current through each of the wires is as follows: 1₁ = 309 A, 12 = 340 A, 13 = 353 A, 14 = 223 A, and is = 312 A. What is the magnitude of the force per unit length on wire 1 due to the other wires? i N/m Z 2 d→→ ←d 3 d 4 d 5 O-Y y
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