The figure below is square loop carrying current I-15 A placed in the field B= 28 + 15ý mWb/m ,The vector torque on the square loop is %3D +2,-2, 0) (-2, 2, 0) (2,-2, 0) (2, 2, 0) a. -3.60áx+6.72ây N.m. b.-360ay+6.72áz N.m C-8.60âx-6.72áz N.m Od.1.80áx-6.72áy N.m e. 10.80áx+20.16äy N.m 1. 10.80ax-13.44ây N.m

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The figure below is square loop carrying current I-15 A placed in the field
B=28 + 15y mWb/m,The vector torque on the square loop is
(+2,-2, 0)
(-2, 2, 0)
(2,-2, 0)
(2, 2, 0)
a.-3.60áx+6.72ây N.m
b.-3.60áy+6.72az N.m
C-3.60áx-6.72âz N.m
Od.1.80áx-6.72ây N.m
De.10.80áx+20.16ây N.m
1. 10.80ax-13.44ây N.m
Transcribed Image Text:The figure below is square loop carrying current I-15 A placed in the field B=28 + 15y mWb/m,The vector torque on the square loop is (+2,-2, 0) (-2, 2, 0) (2,-2, 0) (2, 2, 0) a.-3.60áx+6.72ây N.m b.-3.60áy+6.72az N.m C-3.60áx-6.72âz N.m Od.1.80áx-6.72ây N.m De.10.80áx+20.16ây N.m 1. 10.80ax-13.44ây N.m
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