The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (Omega). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + (Q/C) = E(t) since the current is I = (dQ/dt), we have R(dQ/dt) + (1/C)Q= E(t) Suppose the resistance is 30 ohms, the capacitance is 0.1 Farads, a battery gives a constant voltage of 40 volts, and the initial charge is Q(0)=0C. Find the charge and the current at time t. Q(t)=? I(t)=?
The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (Omega). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + (Q/C) = E(t) since the current is I = (dQ/dt), we have R(dQ/dt) + (1/C)Q= E(t) Suppose the resistance is 30 ohms, the capacitance is 0.1 Farads, a battery gives a constant voltage of 40 volts, and the initial charge is Q(0)=0C. Find the charge and the current at time t. Q(t)=? I(t)=?
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (Omega). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives
RI + (Q/C) = E(t)
since the current is I = (dQ/dt), we have
R(dQ/dt) + (1/C)Q= E(t)
Suppose the resistance is 30 ohms, the capacitance is 0.1 Farads, a battery gives a constant voltage of 40 volts, and the initial charge is Q(0)=0C.
Find the charge and the current at time t.
Q(t)=?
I(t)=?
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