The fat, glyceryl trioleate (C57H10406), is metabolized via the following reaction. Given the enthalpies of formation, calculate the energy (kJ) when 1.00 g of this fat reacts. C57H10406(s) + 80 O2(g) ---> 57 CO2(g) + 52 H2O(1) AH;° C57H10406 = -70870 kJ/mole AH;° H2O(1) = -285.8 kJ/mole AH;° CO2(g) = -393.5 kJ/mole %3D 40.4 33.4 37.9 42.6 30.2
The fat, glyceryl trioleate (C57H10406), is metabolized via the following reaction. Given the enthalpies of formation, calculate the energy (kJ) when 1.00 g of this fat reacts. C57H10406(s) + 80 O2(g) ---> 57 CO2(g) + 52 H2O(1) AH;° C57H10406 = -70870 kJ/mole AH;° H2O(1) = -285.8 kJ/mole AH;° CO2(g) = -393.5 kJ/mole %3D 40.4 33.4 37.9 42.6 30.2
Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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I don’t understand energy questions:(
![The fat, glyceryl trioleate (C57H10406), is metabolized via the following reaction. Given the
enthalpies of formation, calculate the energy (kJ) when 1.00 g of this fat reacts.
C57H10406(s) + 80 O2(g)
---> 57 CO2(g) + 52 H2O(1)
AH;° C57H10406 = -70870 kJ/mole
AH÷° H2O(1) = -285.8 kJ/mole
AH;° CO2(g) = -393.5 kJ/mole
O 40.4
33.4
O 37.9
42.6
30.2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87eb4351-3528-4277-b4ab-c20f32e33033%2Fb3bfc9c6-50f5-44ec-a872-861d08361853%2F3pq29cf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The fat, glyceryl trioleate (C57H10406), is metabolized via the following reaction. Given the
enthalpies of formation, calculate the energy (kJ) when 1.00 g of this fat reacts.
C57H10406(s) + 80 O2(g)
---> 57 CO2(g) + 52 H2O(1)
AH;° C57H10406 = -70870 kJ/mole
AH÷° H2O(1) = -285.8 kJ/mole
AH;° CO2(g) = -393.5 kJ/mole
O 40.4
33.4
O 37.9
42.6
30.2
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