The expected rainfall for the area was approximately 6.0 inches, which would have created about 1.75 liters of standing water per square foot. How much NaCl, in grams, per square foot would have to be used to prevent ice formation if the temperature was only supposed to reach -2.5 C°? The kf of water is 1.86 1/C*mc and the density is 1 g/mL.
A recent snowstorm had the potential to create icy road conditions, which led to the closure of several roads in the area. One way ice on the road could be reduced is to apply a layer of NaCl.
The expected rainfall for the area was approximately 6.0 inches, which would have created about 1.75 liters of standing water per square foot. How much NaCl, in grams, per square foot would have to be used to prevent ice formation if the temperature was only supposed to reach -2.5 C°? The kf of water is 1.86 1/C*mc and the density is 1 g/mL.
To solve thia we will use the formula for calculation of depression in freezing point.
∆Tf = i• Kf •m
Where ,
∆Tf = depression in freezing point .
i = van't Hoff factor
Kf = freezing point depression constant .
m = molality of solution .
From this we will calculate molality of the solution first .
Then the mass of Nacl.
Step by step
Solved in 4 steps
